Use the TI-84 Plus calculator to find the z -scores that bound the middle 88% of the area under the standard normal curve. Enter the answers in ascending order and round to two decimal places. The z -scores for the given area are and .

Use the TI-84 Plus calculator to find the z -scores that bound the middle 88% of the area under the standard normal curve. Enter the answers in ascending order and round to two decimal places. The z -scores for the given area are and .

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9616. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.) - X - X Standard normal table (page 1) Standard normal table (page 2) - 3.3 .0004 0005 .0003 .0004 .0004 .0004 .0004 .0004 .0005 .0005 .0005 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 - 3.2 .0005 .0005 .0006 .0006 .0006 .0006 .0006 .0007 .0007 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 3.1 .0007 .0007 .0008 .0008 .0008 .0008 .0009 .0009 .0009 .0010 0.4 .6554 .6591 .6628 .6700 .6736 .6772 .6808 .6844 .6879 .6664 - 3.0 – 2.9 .0010 .0010 .0011 .0011 .0011 .0012 .0012 .0013 .0013 .0013 .6915 .7019 .7088 .7422…
Use the TI-B4 calculator to find the z-score for which the area to its left is 0.12. Round the answer to two decimal places, The z-score for the given area is
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Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0129. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decipaall eaundad to thcee deeisel elese apeaded - X Standard normal table (page 2) Standard normal table (page 1) Standard Normal Distribution Standard Normal Distribution Critical Values Critical Values Level of Confidence c Level of Confidence c 0.80 1.28 0.80 1.28 0.90 1.645 Area 0.90 1.645 0.95 1.96 0.95 1.96 0.99 2.575 0.99 2.575 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .09 .08 .07 .06 05 .04 .03 .02 .01 .00 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 - 3.4 - 3.3 - 3.2 - 3.1 - 3.0 - 2.9 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0.1 .5398 .5438 .5478 .5517…
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9945 If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.)
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Using the standard normal table in the Toolbox, determine a Z-value. Each response must include three numerical values and be rounded to the hundredths place. Question 1 The cumulative area to Z is 0.80. Question 2 The cumulative area to Z is 0.1762. Question 3 The area between Z and negative infinity is 0.6664. Question 4 The area between Z and positive infinity is 0.119.
The mean height of women in a country (ages 20 - 29) is 64.3 inches. A random sample of 70 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? Assume o = 2.86. The probability that the mean height for the sample is greater than 65 inches is (Round to four decimal places as needed.)
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