**Title: Understanding Standard Scores and Percentiles****Instructions:**Use the table provided to find the standard score (z-score) and corresponding percentile for the given data values:1. A data value 1.6 standard deviations below the mean.2. A data value 1.3 standard deviations above the mean.3. A data value 0.8 standard deviation below the mean.**Calculation Inputs:**- The standard score is _____ and the percentile is _____.- The standard score is _____ and the percentile is _____.- The standard score is _____ and the percentile is _____.**Table: Standard Scores and Percentiles for a Normal Distribution**This detailed table represents the relationship between z-scores and percentiles:| z-score | Percentile | z-score | Percentile | z-score | Percentile ||---------|------------|---------|------------|---------|------------|| -3.0 | 0.13 | -1.0 | 15.87 | 0.0 | 50.00 || -2.9 | 0.19 | -0.9 | 18.41 | 0.1 | 53.98 || -2.8 | 0.39 | -0.8 | 20.99 | 0.2 | 57.93 || -2.7 | 0.64 | -0.7 | 22.66 | 0.3 | 61.79 || -2.6 | 1.02 | -0.6 | 25.38 | 0.4 | 65.54 || -2.5 | 1.50 | -0.5 | 27.43 | 0.5 | 69.15 || -2.4 | 2.05 | -0.4 | 30.85 | 0.6 | 72.57 || -2.3 | 3.21 | -0.3 | 32.10 | 0.7 | 75.80 || -2.2 | 3.67 | -0.2 | 37.57

The data value are given by using this value the standard scores and percentiles are to be otained.

Answered: Use the table to find the standard…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). E Click the icon to view the data. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 H,: Ha #0 O B. Ho: Ha #0 H1: Hd =0 O C. Ho: Ha #0 O D. Ho: Ha = 0 H1: Hd 0
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.10 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). Click the icon to view the data In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. H9: Ha =0 H1: Ha 0
The table below represents a frequency distribution of the heights in centimeters of all 50 members of a club: Height (cm) 160 ≤x≤170 170
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
Which is not a measure of dispersion? a. Mean b. Standard deviation c. Variance d. Range
I vacuum cleaners. The weights are classified according to vacuum cleaner type. At a=0.10, can you conclude that at least one mean vacuum cleaner weight is different The table available below shows the weights (in pounds) for a sample from the others? E Click the icon to view the vacuum cleaner weight data. Let Hgu. PBLU and PTC represent the mean weights for bagged upright, bagless upright, and top canister vacuums respectively. What are the hypotheses for this test? O A. Ho: Heu * PBLU HTC H PBU PBLU =HTC Weight of Vacuum Cleaners by Type O B. Ho: At least one of the means is different. H PBu = HBLUu =PTC &c. Họ: PBU = HBLU =HTC Bagged upright 22 19 Bagless upright Top canister 21 22 23 25 H: At least one of the means different. 17 20 15 18 18 19 O D. Ho: PBU = PBLU "HTC 23 20 26 25 22| 23 Ha: Peu * PBLU *HTC What is the test statistic? Print Done F= (Round to two decimal places as needed.)
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