Use the table below to find the percentage of data items in a normal distribution that lie between z= 1.2 and z 2.2. Z-Score 0.1 0.2 0.3 0.4 0.5 Percentile 53.98 57.93 61.79 65.54 69.15 72.57 75.80 78.81 81.5984.13 1.5 0.6 0.7 0.8 0.9 1.0 1.4 Percentile 86.43 88.49 90.32 91.92 93.32 94.52 95.54 96.41 97.13 97.72 Z-score 1.1 1.2 1.3 1.6 1.7 1.8 1.9 2.0 Z-score 2.1 2.4 2.5 Percentile 98.21 98.61 98.93 99.18 99.38 99.53 99.65 99.74 99.81 99.87 2.2 2.3 2.6 2.7 2.8 2.9 3.0 The percentage of data items in a normal distribution that lie between z = 1.2 and z = 2.2 is %. (1,1) More Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check re to search 99+ 67°F CI

Use the table below to find the percentage of data items in a normal distribution that lie between z= 1.2 and z 2.2. Z-Score 0.1 0.2 0.3 0.4 0.5 Percentile 53.98 57.93 61.79 65.54 69.15 72.57 75.80 78.81 81.5984.13 1.5 0.6 0.7 0.8 0.9 1.0 1.4 Percentile 86.43 88.49 90.32 91.92 93.32 94.52 95.54 96.41 97.13 97.72 Z-score 1.1 1.2 1.3 1.6 1.7 1.8 1.9 2.0 Z-score 2.1 2.4 2.5 Percentile 98.21 98.61 98.93 99.18 99.38 99.53 99.65 99.74 99.81 99.87 2.2 2.3 2.6 2.7 2.8 2.9 3.0 The percentage of data items in a normal distribution that lie between z = 1.2 and z = 2.2 is %. (1,1) More Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check re to search 99+ 67°F CI

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Draw a normal curve with µ= 70 and o = 19. Label the mean and the inflection points. ..... Choose the correct graph of the normal curve below. A. В. OC. 51 70 89 70 89 108 32 51 70
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
Use the normal distribution of IQ scores, which has a mean of 95 and a standard deviation of 12, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set Standard score % Standard score % −3.0 0.13 0.1 53.98 −2.5 0.62 0.5 69.15 −2 2.28 0.9 81.59 −1.5 6.68 1 84.13 −1 15.87 1.5 93.32 −0.9 18.41 2 97.72 −0.5 30.85 2.5 99.38 −0.1 46.02 3 99.87 0 50.00 3.5 99.98 The percentage of scores between 65 and 113 is __?
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
Use the standard normal distribution table to determine the percent of data between z=1.04 and z=1.32. The percent of data between z=1.04 and z=1.32 is
find the actual percentage in the data set, sort the DRIVE variable and count how many of the data points are less than 25 out of the total 35 data points. That is the actual percentage. How does this compare with your prediction? Mean: 57.457 Standard deviation: 26.539 Predicted percentage: 0.110 Drive: 44 20 88 6 71 42 76 63 61 63 84 28 55 33 88 80 86 83 5 85 25 25 54 54 81 73 29 76 78 77 42 65 71 94 6
Find Pas, that is find 90 percentile of z-score from the standard normal distribution. 6.