Use the table below to find the percentage of data items in a normal distribution that lie between z=0.4 and z 2.8.0.50.9 1.0Percentile 53.98 57.93 61.79 65.54 69.15 72.57 75.80 78.81 81.59 84.131.8 1.9 20Percentile 86.43 88.49 90.32 91.92 93.32 94.52 95.54 96 41/97 13 97.72Z-Score0.1 0.2 0.30.60,70.8Z-Score1.11.2 1.3 14 15 16 1.73.0Percentile 98.21 98.61 98.93 99.18 99.38 99.53 99.65 99.74 99.81 99.87Z-SCore2.12.22.32.42.5 26 2.72.82.9The percentage of data items in a normal distribution that lie between z = 0.4 and z = 2.8 is %.arcesensClear allCheck arView an exampleGet more help -Help me solve thisI Terms of Use L Pivacy Policy PermissionsConvright 2022 Pearson Education Inc.All rights reserved

The question is based on a standard normal dist. Given : The percentile for z = 0.4 is 65.54 that…

Answered: Use the table below to find the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Calculate the z-score for the largest value and interpret it in terms of standard deviations. Do the same for the smallest value N: 50 Mean:28.766 SE Mean: 0.476 St.Dev: 3.369 Min: 21.300 Q1: 26.375 Median: 29.400 Q3: 31.150 Max: 35.100
Use the standand normal distribution table to determine the percent of data between z= -1.91 and z 1.17 The percent of data between z= -1.91 and z = 1.17 is what?
A psychologist believes that youths identified as lesbian, gay, or bisexual already know their sexual orientation before they turned 18. To verify this, she took a random sample of 654 young adults that identified as lesbian, gay, or bisexual and asked them the age when they first realized their sexual orientation. It is known that the mean age when a young adult first realized they might be lesbian, gay, or bisexual is normally distributed. R COMMANDER OUTPUT sd se (mean) mean n 14.72199 14.9814 0.57568 654 95 percent confidence interval: 13.572 15.872
Draw a normal curve with µ= 70 and o = 19. Label the mean and the inflection points. ..... Choose the correct graph of the normal curve below. A. В. OC. 51 70 89 70 89 108 32 51 70
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
Identify the z-score corresponding to the indicated percentile. For the standard normal curve, find the z-score that corresponds to the third quartile. 0.77 -0.23 0.67 -0.67
what proportation of a normal distribution is located between each of the following z-score boundaries? a. z=-1.64 and z=+1.64 b. z=-1.96 and z=+1.96 c. z=-1.00 and z=+1.00
What percentage of a normal distribution cooresponds to z scores greater than +0.63? a. 23.57% b. 76.43% c. 73.57% d. 26.43%
2 Use the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a z-score of −0.85. z-score -1.00 -0.95 -0.90 -0.85 -0.80 -0.75 -0.70 Percentile 15.87 17.11 18.41 19.77 21.19 22.66 24.20 z-score -0.65 -0.60 -0.55 -0.50 -0.45 -0.40 -0.35 Percentile 25.78 27.43 29.12 30.85 32.64 34.46 36.32 z-score -0.30 -0.25 -0.20 -0.15 -0.10 -0.05 0.00 Percentile 38.21 40.13 42.07 44.04 46.02 48.01 50.00 a. The percentage of data items that lie below the z-score is ______%. b. b. above a z-score of −0.85: ________.
Read the z statistic from the normal distribution table. For a one-tailed test (lower tail) using a = 0.0618, z = -0.78 O-1.54. 0.48 -1.645.
Use the standard normal distribution table to determine the percent of data between z=1.04 and z=1.32. The percent of data between z=1.04 and z=1.32 is
Calculate the mean deviation from the mean for the following distribution : Marks No. of students : 0–10 20-30 15 10–20 30-40 40-50 : 5 16 6

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