Use the table below to answer the following question: Substance Bond Type Density Water Polar covalent 1.0 g/mL Oil Nonpolar covalent 0.91 g/mL Chloroform Polar covalent 1.49 g/mL Ammonia Polar covalent 0.73 g/mL Gasoline Nonpolar covalent 0.70 g/mL Polyethylene Nonpolar covalent 0.98 g/mL An unknown substance dissolves in water but separates and floats in oil. What is the identity of the unknown substance and why? O A. Chloroform because polar substances dissolve in water and the density must be greater than 0.91 g/mL for it to float in the oil. O B. Ammonia because polar substances dissolve in water and the density must be less than 0.91 g/mL for it to float in the oil. O C. Gasoline because nonpolar substances dissolve in water and the density must be less than 0.91 g/mL for it to float in the oil. O D. Polyethylene because nonpolar substances dissolve in water and the density must be greater than 0.91 g/mL for it to float in the oil.
Use the table below to answer the following question: Substance Bond Type Density Water Polar covalent 1.0 g/mL Oil Nonpolar covalent 0.91 g/mL Chloroform Polar covalent 1.49 g/mL Ammonia Polar covalent 0.73 g/mL Gasoline Nonpolar covalent 0.70 g/mL Polyethylene Nonpolar covalent 0.98 g/mL An unknown substance dissolves in water but separates and floats in oil. What is the identity of the unknown substance and why? O A. Chloroform because polar substances dissolve in water and the density must be greater than 0.91 g/mL for it to float in the oil. O B. Ammonia because polar substances dissolve in water and the density must be less than 0.91 g/mL for it to float in the oil. O C. Gasoline because nonpolar substances dissolve in water and the density must be less than 0.91 g/mL for it to float in the oil. O D. Polyethylene because nonpolar substances dissolve in water and the density must be greater than 0.91 g/mL for it to float in the oil.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Use the table below to answer the following question:
Substance
Bond Type
Density
Water
Polar covalent
1.0 g/mL
Oil
Nonpolar covalent
0.91 g/mL
Chloroform
Polar covalent
1.49 g/mL
Ammonia
Polar covalent
0.73 g/mL
Gasoline
Nonpolar covalent
0.70 g/mL
Polyethylene
Nonpolar covalent
0.98 g/mL
An unknown substance dissolves in water but separates and floats in oil. What is the identity of the unknown substance and why?
O A. Chloroform because polar substances dissolve in water and the density must be greater than 0.91 g/mL for it to float in the oil.
O B. Ammonia because polar substances dissolve in water and the density must be less than 0.91 g/mL for it to float in the oil.
O C. Gasoline because nonpolar substances dissolve in water and the density must be less than 0.91 g/mL for it to float in the oil.
D. Polyethylene because nonpolar substances dissolve in water and the density must be greater than 0.91 g/mL for it to float in the
oil.
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