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Use the substitution u = 8x - 1 to find the following indefinite integral. Check your answer by differentiation. - 16x sin (8x2 - 1) dx ..... 16x sin (8x2 - 1) dx =

Use the substitution u = 8x - 1 to find the following indefinite integral. Check your answer by differentiation. - 16x sin (8x2 - 1) dx ..... 16x sin (8x2 - 1) dx =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the substitution u = 8x - 1 to find the following indefinite integral. Check your answer by differentiation. S - – 16x sin (8x2 – 1) dx ..... - 16x sin (8x2 – 1) dx =
Transcribed Image Text:Use the substitution u = 8x - 1 to find the following indefinite integral. Check your answer by differentiation. S - – 16x sin (8x2 – 1) dx ..... - 16x sin (8x2 – 1) dx =
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