Use the structure of each of the following molecules or ions, predict a) Number of electron domains. Explain your reasoning b) Hybridization. Explain your reasoning c) Electron geometry. Explain your reasoning d) Molecular geometry. Explain your reasoning e) Polarity - if they will be polar or not. Explain your reasoning. O=C=0 H-Sn-H

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Chapter1: Chemical Foundations
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**Instructions:**

Use the structure of each of the following molecules or ions to predict:

a) Number of electron domains. Explain your reasoning.  
b) Hybridization. Explain your reasoning.  
c) Electron geometry. Explain your reasoning.  
d) Molecular geometry. Explain your reasoning.  
e) Polarity - if they will be polar or not. Explain your reasoning.  

**Molecular Structures:**

1. **H-Sn-H**
   - Structure: Tin (Sn) central atom bonded to two hydrogen (H) atoms.

2. **\[O=C=O\]** (Carbon Dioxide)
   - Structure: Linear molecule with carbon (C) central atom double bonded to two oxygen (O) atoms.

3. **\[H- \overset{}{C} - Cl \]**
   - Structure: Central carbon (C) atom bonded to hydrogen (H) and two chlorine (Cl) atoms in a tetrahedral fashion.

4. **\[ S \\ \ | \\ P \\ / \\ Cl \]**
   - Structure: Phosphorus (P) central atom bonded to chlorine (Cl) atoms and a sulfur (S) atom, forming a trigonal pyramidal shape.

**Diagrams:**

1. **H-Sn-H**: 
   - Appears linear with Sn as the central atom.

2. **O=C=O**:
   - Linear diagram; carbon is central with oxygen atoms on both sides.

3. **C-H2Cl2**:
   - Depicts C with single bonds to H and Cl, tetrahedral arrangement is implied.

4. **Cl3PS**:
   - Shows a trigonal pyramidal shape with P as the central atom bonded to three Cl atoms and one S atom.

By analyzing each molecule or ion, students should determine the electron domains around the central atom, the appropriate hybridization, the overall electron and molecular geometry, and the resulting polarity based on the molecular symmetry and electronegativity differences.
Transcribed Image Text:Below is a transcription and detailed explanation for educational purposes: **Instructions:** Use the structure of each of the following molecules or ions to predict: a) Number of electron domains. Explain your reasoning. b) Hybridization. Explain your reasoning. c) Electron geometry. Explain your reasoning. d) Molecular geometry. Explain your reasoning. e) Polarity - if they will be polar or not. Explain your reasoning. **Molecular Structures:** 1. **H-Sn-H** - Structure: Tin (Sn) central atom bonded to two hydrogen (H) atoms. 2. **\[O=C=O\]** (Carbon Dioxide) - Structure: Linear molecule with carbon (C) central atom double bonded to two oxygen (O) atoms. 3. **\[H- \overset{}{C} - Cl \]** - Structure: Central carbon (C) atom bonded to hydrogen (H) and two chlorine (Cl) atoms in a tetrahedral fashion. 4. **\[ S \\ \ | \\ P \\ / \\ Cl \]** - Structure: Phosphorus (P) central atom bonded to chlorine (Cl) atoms and a sulfur (S) atom, forming a trigonal pyramidal shape. **Diagrams:** 1. **H-Sn-H**: - Appears linear with Sn as the central atom. 2. **O=C=O**: - Linear diagram; carbon is central with oxygen atoms on both sides. 3. **C-H2Cl2**: - Depicts C with single bonds to H and Cl, tetrahedral arrangement is implied. 4. **Cl3PS**: - Shows a trigonal pyramidal shape with P as the central atom bonded to three Cl atoms and one S atom. By analyzing each molecule or ion, students should determine the electron domains around the central atom, the appropriate hybridization, the overall electron and molecular geometry, and the resulting polarity based on the molecular symmetry and electronegativity differences.
Expert Solution
Step 1
Molecule electron domain hybridizaion molecular geometry polarity
SnCl4 4 SP3 TETRAHYDRAL NONPOLAR
CO2 4 SP3 LINEAR NONPOLAR
CCl2H2 4 SP3 TETRAHYDRAL NONPOLAR
PCl3S 4 SP3 TETRAHYDRAL POLAR
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