Use the standard normal table to find the specified area. Between z=−0.45 and -1.72
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- Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9864. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores.find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. z=-0.85 and z=1.29Find the area of the indicated region under the standard normal curve. -1.5 & 0.9.
- Use the standard normal table to find the z-score that corresponds to the cumulative area 0.9616. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decimal rounded to three decimal places as needed.) - X - X Standard normal table (page 1) Standard normal table (page 2) - 3.3 .0004 0005 .0003 .0004 .0004 .0004 .0004 .0004 .0005 .0005 .0005 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 - 3.2 .0005 .0005 .0006 .0006 .0006 .0006 .0006 .0007 .0007 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 3.1 .0007 .0007 .0008 .0008 .0008 .0008 .0009 .0009 .0009 .0010 0.4 .6554 .6591 .6628 .6700 .6736 .6772 .6808 .6844 .6879 .6664 - 3.0 – 2.9 .0010 .0010 .0011 .0011 .0011 .0012 .0012 .0013 .0013 .0013 .6915 .7019 .7088 .7422…Use technology to find the indicated area under the standard Normal curve. Include an appropriately labeled sketch of the Normal curve and shade the appropriate region. a. Find the area in a standard Normal curve to the left of 1.63. b. Find the area in a standard Normal curve to the right of 1.63. Remember that the total area under the curve is 1. a. Which graph below shows the area in a standard Normal curve to the left of 1.63? A. 1.63 A graph contains a Normal curve, plotted over a horizontal axis, which extends between the left and right edges of the graph and has a peak at the horizontal center. Approximately 25% of the way from the graph’s right edge, a vertical line segment with labeled horizontal coordinate 1.63 extends from the horizontal axis to the curve. The area below the curve and to the left of the vertical line segment is shaded. Your answer is correct. B. 1.63…Use the TI-B4 calculator to find the z-score for which the area to its left is 0.12. Round the answer to two decimal places, The z-score for the given area is
- Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0129. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decipaall eaundad to thcee deeisel elese apeaded - X Standard normal table (page 2) Standard normal table (page 1) Standard Normal Distribution Standard Normal Distribution Critical Values Critical Values Level of Confidence c Level of Confidence c 0.80 1.28 0.80 1.28 0.90 1.645 Area 0.90 1.645 0.95 1.96 0.95 1.96 0.99 2.575 0.99 2.575 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .09 .08 .07 .06 05 .04 .03 .02 .01 .00 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 - 3.4 - 3.3 - 3.2 - 3.1 - 3.0 - 2.9 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0.1 .5398 .5438 .5478 .5517…Use the standard normal table to find the area to the left of z=−0.34. The area to the left of z=−0.34 isIn a survey of 1000 eligible voters selected at random, it was found that 200 had a college degree. Additionally, it was found that 80% of those who had a college degree voted in the last presidential election, whereas 46% of the people who did not have a college degree voted in the last presidential election. Assuming that the poll is representative of all eligible voters, find the probability that an eligible voter selected at random will have the following characteristics. (Round your answers to three decimal places.) (a) The voter had a college degree and voted in the last presidential election. (b) The voter did not have a college degree and did not vote in the last presidential election. (c) The voter voted in the last presidential election. (d) The voter did not vote in the last presidential election.
