Use the standard error method to construct a 95% confidence interval for the true proportion of Americans who approve of the indictment of former President Trump interpret your confifence inerval in the context of this situation.

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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5. Use the standard error method to construct a 95% confidence interval for the true proportion of Americans who approve of the indictment of former President Trump

interpret your confifence inerval in the context of this situation.

 

6. Construct a 99% CI using the counting method and the graph.

explain how you determine your 99% CI using the graph given 

interpret your confidence interval in the contect of this situation

10
0
20
30
Part A
For questions #1-6, reference the following scenario and bootstrap distribution.
40
60
50
On April 3, 2023, CNN conducted a survey to determine the number of Americans who approve of the indictment of former President Donald Trump. In a
representative random sample of 1048, a total of 629 voiced approval of the indictment.
70
0.54
Since this statistic is only a sample of all Americans, a confidence interval is needed to predict the true proportion of Americans who support the indictment of
the former President. Below is the bootstrap distribution for this proportion.
Bootstrap Dotplot of
90
80
Proportion
Left Tail OTwo-Tail O Right Tail
0.55
0.56
DOD
0.57
PO O DO
0.58
COU
CO DO
0 00
0.59
BUDD
OD D
2009
0.00
0.601
DO
c
0.9
.. OD
00
00 DD DD . .
00
0.61
0.62
00
BO
Go
0.63
samples - 1000
mean 0.601
std. error = 0.015
0.64
Original Sample
Count
629
Bootstrap Sample
Count
641
Sample Size
Sample Size
1048
1049
Proportion
Proportion
0.600
0.612
del
Transcribed Image Text:10 0 20 30 Part A For questions #1-6, reference the following scenario and bootstrap distribution. 40 60 50 On April 3, 2023, CNN conducted a survey to determine the number of Americans who approve of the indictment of former President Donald Trump. In a representative random sample of 1048, a total of 629 voiced approval of the indictment. 70 0.54 Since this statistic is only a sample of all Americans, a confidence interval is needed to predict the true proportion of Americans who support the indictment of the former President. Below is the bootstrap distribution for this proportion. Bootstrap Dotplot of 90 80 Proportion Left Tail OTwo-Tail O Right Tail 0.55 0.56 DOD 0.57 PO O DO 0.58 COU CO DO 0 00 0.59 BUDD OD D 2009 0.00 0.601 DO c 0.9 .. OD 00 00 DD DD . . 00 0.61 0.62 00 BO Go 0.63 samples - 1000 mean 0.601 std. error = 0.015 0.64 Original Sample Count 629 Bootstrap Sample Count 641 Sample Size Sample Size 1048 1049 Proportion Proportion 0.600 0.612 del
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