Use the Squeeze Theorem to find the limit of the sequence. sin() 4n sin

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
**Title: Using the Squeeze Theorem to Find the Limit of a Sequence**

**Problem Statement:**

Use the Squeeze Theorem to find the limit of the sequence:  
\[ 4n \sin\left(\frac{1}{n}\right) \]

**Explanation:**

The problem requires applying the Squeeze Theorem to determine the limit of the sequence as \( n \) approaches infinity.

**Correctness Check:**

A text box is provided for the answer. There is a red 'x' indicating an incorrect or incomplete solution attempt.

**Conceptual Approach:**

1. **Understanding the Squeeze Theorem:**
   - The Squeeze Theorem states that if \( a_n \leq b_n \leq c_n \) for all \( n \) beyond a certain point, and if \(\lim_{n \to \infty} a_n = \lim_{n \to \infty} c_n = L\), then \(\lim_{n \to \infty} b_n = L\).

2. **Sequence Analysis:**
   - As \( n \to \infty \), \(\frac{1}{n} \to 0\).
   - We know the property of sine: \(-1 \leq \sin(x) \leq 1\) for any real number \( x \).
   - Therefore, \(-\frac{1}{n} \leq \sin\left(\frac{1}{n}\right) \leq \frac{1}{n}\).

3. **Applying the Squeeze Theorem:**
   - Multiply throughout by \( 4n \): \(-4 \leq 4n \sin\left(\frac{1}{n}\right) \leq 4\).
   - The limits of \(-4\) and \(4\) as \( n \to \infty\) are both \(4\).

4. **Conclusion:**
   - By the Squeeze Theorem, \(\lim_{n \to \infty} 4n \sin\left(\frac{1}{n}\right) = 4\).

This concept can be further illustrated with diagrams or examples to deepen understanding.
Transcribed Image Text:**Title: Using the Squeeze Theorem to Find the Limit of a Sequence** **Problem Statement:** Use the Squeeze Theorem to find the limit of the sequence: \[ 4n \sin\left(\frac{1}{n}\right) \] **Explanation:** The problem requires applying the Squeeze Theorem to determine the limit of the sequence as \( n \) approaches infinity. **Correctness Check:** A text box is provided for the answer. There is a red 'x' indicating an incorrect or incomplete solution attempt. **Conceptual Approach:** 1. **Understanding the Squeeze Theorem:** - The Squeeze Theorem states that if \( a_n \leq b_n \leq c_n \) for all \( n \) beyond a certain point, and if \(\lim_{n \to \infty} a_n = \lim_{n \to \infty} c_n = L\), then \(\lim_{n \to \infty} b_n = L\). 2. **Sequence Analysis:** - As \( n \to \infty \), \(\frac{1}{n} \to 0\). - We know the property of sine: \(-1 \leq \sin(x) \leq 1\) for any real number \( x \). - Therefore, \(-\frac{1}{n} \leq \sin\left(\frac{1}{n}\right) \leq \frac{1}{n}\). 3. **Applying the Squeeze Theorem:** - Multiply throughout by \( 4n \): \(-4 \leq 4n \sin\left(\frac{1}{n}\right) \leq 4\). - The limits of \(-4\) and \(4\) as \( n \to \infty\) are both \(4\). 4. **Conclusion:** - By the Squeeze Theorem, \(\lim_{n \to \infty} 4n \sin\left(\frac{1}{n}\right) = 4\). This concept can be further illustrated with diagrams or examples to deepen understanding.
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