Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Title: Using the Squeeze Theorem to Find the Limit of a Sequence**
**Problem Statement:**
Use the Squeeze Theorem to find the limit of the sequence:
\[ 4n \sin\left(\frac{1}{n}\right) \]
**Explanation:**
The problem requires applying the Squeeze Theorem to determine the limit of the sequence as \( n \) approaches infinity.
**Correctness Check:**
A text box is provided for the answer. There is a red 'x' indicating an incorrect or incomplete solution attempt.
**Conceptual Approach:**
1. **Understanding the Squeeze Theorem:**
- The Squeeze Theorem states that if \( a_n \leq b_n \leq c_n \) for all \( n \) beyond a certain point, and if \(\lim_{n \to \infty} a_n = \lim_{n \to \infty} c_n = L\), then \(\lim_{n \to \infty} b_n = L\).
2. **Sequence Analysis:**
- As \( n \to \infty \), \(\frac{1}{n} \to 0\).
- We know the property of sine: \(-1 \leq \sin(x) \leq 1\) for any real number \( x \).
- Therefore, \(-\frac{1}{n} \leq \sin\left(\frac{1}{n}\right) \leq \frac{1}{n}\).
3. **Applying the Squeeze Theorem:**
- Multiply throughout by \( 4n \): \(-4 \leq 4n \sin\left(\frac{1}{n}\right) \leq 4\).
- The limits of \(-4\) and \(4\) as \( n \to \infty\) are both \(4\).
4. **Conclusion:**
- By the Squeeze Theorem, \(\lim_{n \to \infty} 4n \sin\left(\frac{1}{n}\right) = 4\).
This concept can be further illustrated with diagrams or examples to deepen understanding.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F829812ca-fcc6-4eb6-9db8-017261f61931%2F82ae7440-63c0-4c47-b5b8-76ed6d8dcc19%2F80ft5hh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Using the Squeeze Theorem to Find the Limit of a Sequence**
**Problem Statement:**
Use the Squeeze Theorem to find the limit of the sequence:
\[ 4n \sin\left(\frac{1}{n}\right) \]
**Explanation:**
The problem requires applying the Squeeze Theorem to determine the limit of the sequence as \( n \) approaches infinity.
**Correctness Check:**
A text box is provided for the answer. There is a red 'x' indicating an incorrect or incomplete solution attempt.
**Conceptual Approach:**
1. **Understanding the Squeeze Theorem:**
- The Squeeze Theorem states that if \( a_n \leq b_n \leq c_n \) for all \( n \) beyond a certain point, and if \(\lim_{n \to \infty} a_n = \lim_{n \to \infty} c_n = L\), then \(\lim_{n \to \infty} b_n = L\).
2. **Sequence Analysis:**
- As \( n \to \infty \), \(\frac{1}{n} \to 0\).
- We know the property of sine: \(-1 \leq \sin(x) \leq 1\) for any real number \( x \).
- Therefore, \(-\frac{1}{n} \leq \sin\left(\frac{1}{n}\right) \leq \frac{1}{n}\).
3. **Applying the Squeeze Theorem:**
- Multiply throughout by \( 4n \): \(-4 \leq 4n \sin\left(\frac{1}{n}\right) \leq 4\).
- The limits of \(-4\) and \(4\) as \( n \to \infty\) are both \(4\).
4. **Conclusion:**
- By the Squeeze Theorem, \(\lim_{n \to \infty} 4n \sin\left(\frac{1}{n}\right) = 4\).
This concept can be further illustrated with diagrams or examples to deepen understanding.
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