Use the simplex method to solve.The maximum is z =(Simplify your answers.)when X1=and x2Maximize z=12x₁ +10x2x₁ +5x₂ > 23subject to:X1 + X₂ $41X₁ 20, X₂ 20with=

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Answered: Use the simplex method to solve. The…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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For a certain company, the cost for producing a items is 40x + 300 and the revenue for selling x items is 80x – 0.5x². The profit that the company makes is how much it takes in (revenue) minus how much it spends (cost). In economic models, one typically assumes that a company wants to maximize its profit, or at least wants to make a profit! Part a: Set up an expression for the profit from producing and selling x items. We assume that the company sells all of the items that it produces. (Hint: it is a quadratic polynomial.) Part b: Find two values of that will create a profit of $50. The field below accepts a list of numbers or formulas separated by semicolons (e.g. 2; 4; 6 or x + 1; x – 1). The order of the list does not matter. To enter va , type sqrt(a).
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Determine maximum or minimum income, earnings and investments through the vertex of a quadratic equation. Mrs. Miranda has a business selling cookies and biscuits. When you sell "x" items per year, the income is described by the quadratic function: f(x)= 72x – 0.08x2 1. Calculate the number of items you should sell each year for maximum income. 2. What is the maximum income?
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Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit (in dollars) realized from renting out x apartments is given by -10x2 + 1200x − 2000 To maximize the monthly rental profit, how many units should be rented out? What is the maximum monthly profit realizable?
C. Transform the Standard Quadratic function to vertex form.Show your solution 1. y= 4x² +8x –6 2. y =-3x² +18x+7

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Use the simplex method to solve. The maximum is z= when X₁ = (Simplify your answers.) Maximize z=12x₁ +10x2 subject to: x₁ +5x2 2 23 x1 + x₂ 541 X₁ 20, X₂ 20 with and x2 =