Use the Second Derivative Test to prove that if (a,b) is a critical point of f at which f,(a,b) = f,(a,b) = 0 and fxox (a,b) < 0

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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22. Use the Second Derivative Test to prove that if (a,b) is a critical point of f at which f,(a,b) = fy(a,b) = 0 and
fx (a,b) <0<fy(a,b) or fy(a,b) <0<f(a,b), then f has a saddle point at (a,b).
The Second Derivative Test states that if D(x,y)= fx (x,y)fyy(x,y)- (fxy(x,y))², then f has a saddle point at (a,b) if
D(a,b) <0.
Regardless of the point (a,b), (fy(a,b)²20.
If f (a,b) <0<fy(a,b), then f (a,b)fyy(a,b) <0.
Therefore, D(a,b) <0.
If fy (a,b) <0<fx(a,b), then f«(a,b)fyy(a,b) <0.
Therefore, D(a,b)<0.
23. Among all triangles with a perimeter of 3 units, find the dimensions of the triangle with the maximum area. It may be
easiest to use Heron's formula, which states that the area of a triangle with side length a, b, and c is
A = Vs(s-a)(s-b)(s-c), where 2s is the perimeter of the triangle.
The dimensions are a =
unit(s), b=
unit(s), and c=
unit(s). (Use
ascending order.)
Transcribed Image Text:22. Use the Second Derivative Test to prove that if (a,b) is a critical point of f at which f,(a,b) = fy(a,b) = 0 and fx (a,b) <0<fy(a,b) or fy(a,b) <0<f(a,b), then f has a saddle point at (a,b). The Second Derivative Test states that if D(x,y)= fx (x,y)fyy(x,y)- (fxy(x,y))², then f has a saddle point at (a,b) if D(a,b) <0. Regardless of the point (a,b), (fy(a,b)²20. If f (a,b) <0<fy(a,b), then f (a,b)fyy(a,b) <0. Therefore, D(a,b) <0. If fy (a,b) <0<fx(a,b), then f«(a,b)fyy(a,b) <0. Therefore, D(a,b)<0. 23. Among all triangles with a perimeter of 3 units, find the dimensions of the triangle with the maximum area. It may be easiest to use Heron's formula, which states that the area of a triangle with side length a, b, and c is A = Vs(s-a)(s-b)(s-c), where 2s is the perimeter of the triangle. The dimensions are a = unit(s), b= unit(s), and c= unit(s). (Use ascending order.)
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