Use the second derivative test to find the relative extrema of ƒ (x) = √√2x + 2 cos x on the interval [0, 2π]. ㅠ Relative Maximum at x = ☎ because ƒ¹ (7) = 0 and ƒ/1 (7) > 0. Relative Minimum at x = Relative Minimum at x = 4 Relative Maximum at x = O Relative Maximum at x = Relative Minimum at x = Relative Maximum at x = 3π 4 Relative Minimum at x = because ƒ¹ (7) = 0 and ƒ11 (7) < 0. because f(³) = 0 and ƒ11 (³) > 0. 3π 4 5п 4 3π 4 because f1 (³) = 0 and f11 (³1) < 0. 4 3π 4 because ƒ1 (57) because ƒ1 (3³) = = 0 and f11 (5) < 0. = 0 and f11 (³″) > 0. because f¹ (1) = 0 and ƒ11 (7) < 0. because f(3) = 0 and f/l (3) > 0.

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