Use the Schrödinger equation to calculate the energy of a 1-dimensional particle-in-a-box system in which the normalized wave function is 4 = Esin(6x). The box boundaries are at x=0 and x=n/3. The potential energy is zero when 0 < x< and co outside of these boundaries.

Principles of Physics: A Calculus-Based Text
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Chapter28: Quantum Physics
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Problem 47P
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Use the Schrödinger equation to calculate the energy of a 1-dimensional particle-in-a-box system in
which the normalized wave function is 4' =
sin(6x). The box boundaries are at x=0 and x=T/3. The
potential energy is zero when 0 < xs and co outside of these boundaries.
Transcribed Image Text:Use the Schrödinger equation to calculate the energy of a 1-dimensional particle-in-a-box system in which the normalized wave function is 4' = sin(6x). The box boundaries are at x=0 and x=T/3. The potential energy is zero when 0 < xs and co outside of these boundaries.
What is the value of quantum number, n, for a 1-dimensional particle-in-a-box system in which the
normalized wave function is 4' = 2 sin (*).
The box boundaries are at x=0 and x=3Tn. The potential
energy is zero when 0 < x< 3n and ∞ outside of these boundaries.
Transcribed Image Text:What is the value of quantum number, n, for a 1-dimensional particle-in-a-box system in which the normalized wave function is 4' = 2 sin (*). The box boundaries are at x=0 and x=3Tn. The potential energy is zero when 0 < x< 3n and ∞ outside of these boundaries.
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