Use the sample data and confidence level given below to complete parts​ (a) through​ (d).   A drug is used to help prevent blood clots in certain patients. In clinical​ trials, among 4882 patients treated with the​ drug, 182 developed the adverse reaction of nausea. Construct a 99​% confidence interval for the proportion of adverse reactions.       Question content area bottom Part 1 ​a) Find the best point estimate of the population proportion p.   enter your response here ​(Round to three decimal places as​ needed.) Part 2 ​b) Identify the value of the margin of error E.   E=enter your response here ​(Round to three decimal places as​ needed.) Part 3 ​c) Construct the confidence interval.   enter your response here

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A: Given data,x=208n=260p^=xn=208260=45=0.80

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A: Here use formula of length of confidence interval

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A: Formula : The confidence interval formula is CI =

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A: Sample size n=z2(p*q)/e2

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Q: How do you solve? ref W9Q7.

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A: From the given data: x¯=∑xn=80.74=20.175s=∑x2-n x¯2n-1=1628.77-4×20.17524-1=0.4646

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A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

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A: Mean = 56.64 Standard deviation = 14.598 n=100

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A: To calculate: The 97% confidence interval.

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Q: You're considering going to graduate school, and you would like to know how many people would…

A: Given: X= 6, N=28. Therefore, P=XN=628=0.214

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A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.)

A:

Q: ou're considering going to graduate school, and you would like to know how many people would…

A: Given data, n=30 x=7 p=x/n =7/30 =0.23 z-value at 96% confidence is Zc=2.05

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