Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1061 and x = 591 who said "yes." Use a 95% confidence level. | Click the icon to view a table of z scores. ..... a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E =] (Round to three decimal places as needed.) c) Construct the confidence interval. O
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1061 and x = 591 who said "yes." Use a 95% confidence level. | Click the icon to view a table of z scores. ..... a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E =] (Round to three decimal places as needed.) c) Construct the confidence interval. O
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, \( n = 1061 \) and \( x = 591 \) who said "yes." Use a 95% confidence level.
[Click the icon to view a table of z scores.]
---
a) Find the best point estimate of the population proportion \( p \).
[Round to three decimal places as needed.]
\(\square\)
b) Identify the value of the margin of error \( E \).
\( E = \square \)
[Round to three decimal places as needed.]
c) Construct the confidence interval.
\(\square < p < \square\)
[Round to three decimal places as needed.]
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
- A. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
- B. One has 95% confidence that the sample proportion is equal to the population proportion.
- C. 95% of sample proportions will fall between the lower bound and the upper bound.
- D. One has 95% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a5ed048-7cb6-4762-ac8c-8a5f0236d686%2Ff6f7de0f-5bf2-4b71-9956-7c46136ecd55%2Fja4ht6j_processed.png&w=3840&q=75)
Transcribed Image Text:Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, \( n = 1061 \) and \( x = 591 \) who said "yes." Use a 95% confidence level.
[Click the icon to view a table of z scores.]
---
a) Find the best point estimate of the population proportion \( p \).
[Round to three decimal places as needed.]
\(\square\)
b) Identify the value of the margin of error \( E \).
\( E = \square \)
[Round to three decimal places as needed.]
c) Construct the confidence interval.
\(\square < p < \square\)
[Round to three decimal places as needed.]
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
- A. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
- B. One has 95% confidence that the sample proportion is equal to the population proportion.
- C. 95% of sample proportions will fall between the lower bound and the upper bound.
- D. One has 95% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.

Transcribed Image Text:**Standard Normal (z) Distribution Table**
This table provides the probabilities associated with the standard normal distribution (also called z-distribution), which is used in statistics to determine the likelihood of a random variable falling within a particular range of values. The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1.
**Understanding the Table:**
The table is divided into rows and columns that correspond to z-scores. A z-score represents the number of standard deviations a data point is from the mean.
- **Rows (z):** These indicate the whole number and first decimal place of the z-score (e.g., 0.0, 0.1, ..., 2.0).
- **Columns:** Represent the second decimal place of the z-score (e.g., .00, .01, ..., .09).
**Example of Table Usage:**
To find the probability of a z-score of 1.95:
1. Locate the row for 1.9.
2. Move across to the column for .05.
3. The intersection gives the probability: 0.9750.
This means that approximately 97.50% of the data falls below a z-score of 1.95.
### Probability Values:
- **z = 0.0**
- .00: .5000
- .01: .5040
- .09: .5359
- **z = 0.1**
- .00: .5398
- .01: .5438
- .09: .5753
- **z = 1.0**
- .00: .8413
- .01: .8438
- .09: .8599
- **z = 1.5**
- .00: .9332
- .01: .9345
- .09: .9418
- **z = 2.0**
- .00: .9772
- .01: .9778
- .09: .9817
Note: These values are part of the cumulative distribution function (CDF) for the standard normal distribution, representing the area under the curve to the left of the specified z-score.
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