Use the sample data and confidence level given below to complete parts (a) through (d). A research insitute poll asked respondents if they felt vulnerbale to identity theft. In the poll, n=903 and x=590 who said "yes." Use 95% confidence level. a. find the best point of the population proportion p. (Round to three decimal places as needed.)b. Identity the value of the margin of error E.E = c. Construct the confidence level interval. ___ < p < ___d. Write a statement that correctly interprets the confidence interval. Choose to correct Below A. One has 95% confidence that the sample proportion is equal to the population proportion. B. 95% of sample porportions will fall between the lower bound and upper bound.C. One has 95% confidence that the interval from the lower bound to the bound actually does contain the true value of the popuklation porportion. D. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound. 1/31/2021Standard Normal (z) DistributionPOSITIVE z ScoresStandard Normal (z) Distribution: Cumulative Area from the LEFT.00.01.02.0304.05.06.0708.090.0.5000.5040.5080.5120.5160.5199.5239.5279.5319.53590.00.1.5398.5438.5478.5517.5557.5596.5636.5675.5714.57530.10.2.5793.5832.5871.5910.5948.5987.6026.6064.6103.61410.20.3.6179.6217.6255.6293.6331.6368.6406.6443.6480.65170.30.4.6554.6591.6628.6664.6700.6736.6772.6808.6844.68790.40.5.6915.6960.698570197054.7088.7123.7157.7190.72240,50.6.7257.7291732473577389.7422.7454.7486.7517.75490.60.7.7580.7611.7642767377047734.7764.7794.7823.78520.70.8.7881.7910.7939796779958023.8061.8078.8106.81330.80.9815981868212.823882648289.8315.8340.8365.83890.91.084138438846184858508.85318554.85778599.86211.01.186438665.8686.870887298749.8770.8790.8810.88301.11.28849.8869.8888.89078925.8944.8962.8980.8997.90151.21.390329049.9066.90829099.9115.9131.9147.9162.91771.31.4.91929207.9222.923692519265.9279.9292.9306.93191.41.5.9332.9345.9357.9370938293949406.94189429.94411.51.6945294639474.9484.9495.9505.9515.9525.9535.95451.61.795549564.9573.9582.9591.9599.960896169625.96331.71.8.9641.9649.9656.9664.9671.9678.9686.9693.9699.97061.81.997139719.9726.9732.9738.9744.9750.9756.9761.97671.92.0.9772.9778.9783.9788.9793.9798.9803.9808.9812.98172.02.1.9821.9826.9830.9834.9838.9842.9846.9850.9854.98572.12.2.9861.9864.9868.9871.9875.9878.9881.9884.9887.98902.22.3989398969898.99019904.9906,9909.9911.9913.99162.32.499189920.9922.9925.9927.9929.9931.9932.9934.99362.42.5.993899409941.994399459946.9948.9949.9951.99522.52.699639965.9956.9957.9959.9960.99619962.9963.99642.62.79965.9966.9967.9968.9969.9970.9971.9972.9973.99742.72.89974.9975.9976.9977.9977.9978.9979.9979.9980.99812.82.9.99819982.9982.9983.9984.9984.9985.9985.9986.99862.93.0.9987.9987.9987.9988.9988.9989.9989.9989.9990.99903.03.1.9990.99919991.9991.9992.9992.9992.9992.9993.99933.13.2.9993.9993.9994.9994.9994.99949994.9995999599953.23.399959995.999599969996.9996.9996.9996.9996.99973.33.4.9997.9997.9997.99979997.9997,9997.9997.9997.99983.43.50. and up99993.50. and up.0005.01.0203.04.06.07.08.09Standard Normal (z) Distribution: Cumulative Area from the LEFT

Name: Use the sample data and confidence level given below to complete parts
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: Use the sample data and confidence level given below to complete parts (a) through (d). A research insitute poll asked respondents if they felt vulnerbale to identity theft. In the poll, n=903 and x=590 who said "yes." Use 95% confidence level. a. fi

Answered: Use the sample data and confidence…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

Use the sample data and confidence level given below to complete parts (a) through (d).

A research insitute poll asked respondents if they felt vulnerbale to identity theft. In the poll, n=903 and x=590 who said "yes." Use 95% confidence level.

a. find the best point of the population proportion p. (Round to three decimal places as needed.)

b. Identity the value of the margin of error E.

E =

c. Construct the confidence level interval.

___ < p < ___

d. Write a statement that correctly interprets the confidence interval. Choose to correct Below

A. One has 95% confidence that the sample proportion is equal to the population proportion.

B. 95% of sample porportions will fall between the lower bound and upper bound.

C. One has 95% confidence that the interval from the lower bound to the bound actually does contain the true value of the popuklation porportion.

D. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

1/31/2021
Standard Normal (z) Distribution
POSITIVE z Scores
Standard Normal (z) Distribution: Cumulative Area from the LEFT
.00
.01
.02
.03
04
.05
.06
.07
08
.09
0.0
.5000
.5040
.5080
.5120
.5160
.5199
.5239
.5279
.5319
.5359
0.0
0.1
.5398
.5438
.5478
.5517
.5557
.5596
.5636
.5675
.5714
.5753
0.1
0.2
.5793
.5832
.5871
.5910
.5948
.5987
.6026
.6064
.6103
.6141
0.2
0.3
.6179
.6217
.6255
.6293
.6331
.6368
.6406
.6443
.6480
.6517
0.3
0.4
.6554
.6591
.6628
.6664
.6700
.6736
.6772
.6808
.6844
.6879
0.4
0.5
.6915
.6960
.6985
7019
7054
.7088
.7123
.7157
.7190
.7224
0,5
0.6
.7257
.7291
7324
7357
7389
.7422
.7454
.7486
.7517
.7549
0.6
0.7
.7580
.7611
.7642
7673
7704
7734
.7764
.7794
.7823
.7852
0.7
0.8
.7881
.7910
.7939
7967
7995
8023
.8061
.8078
.8106
.8133
0.8
0.9
8159
8186
8212
.8238
8264
8289
.8315
.8340
.8365
.8389
0.9
1.0
8413
8438
8461
8485
8508
.8531
8554
.8577
8599
.8621
1.0
1.1
8643
8665
.8686
.8708
8729
8749
.8770
.8790
.8810
.8830
1.1
1.2
8849
.8869
.8888
.8907
8925
.8944
.8962
.8980
.8997
.9015
1.2
1.3
9032
9049
.9066
.9082
9099
.9115
.9131
.9147
.9162
.9177
1.3
1.4
.9192
9207
.9222
.9236
9251
9265
.9279
.9292
.9306
.9319
1.4
1.5
.9332
.9345
.9357
.9370
9382
9394
9406
.9418
9429
.9441
1.5
1.6
9452
9463
9474
.9484
.9495
.9505
.9515
.9525
.9535
.9545
1.6
1.7
9554
9564
.9573
.9582
.9591
.9599
.9608
9616
9625
.9633
1.7
1.8
.9641
.9649
.9656
.9664
.9671
.9678
.9686
.9693
.9699
.9706
1.8
1.9
9713
9719
.9726
.9732
.9738
.9744
.9750
.9756
.9761
.9767
1.9
2.0
.9772
.9778
.9783
.9788
.9793
.9798
.9803
.9808
.9812
.9817
2.0
2.1
.9821
.9826
.9830
.9834
.9838
.9842
.9846
.9850
.9854
.9857
2.1
2.2
.9861
.9864
.9868
.9871
.9875
.9878
.9881
.9884
.9887
.9890
2.2
2.3
9893
9896
9898
.9901
9904
.9906
,9909
.9911
.9913
.9916
2.3
2.4
9918
9920
.9922
.9925
.9927
.9929
.9931
.9932
.9934
.9936
2.4
2.5
.9938
9940
9941
.9943
9945
9946
.9948
.9949
.9951
.9952
2.5
2.6
9963
9965
.9956
.9957
.9959
.9960
.9961
9962
.9963
.9964
2.6
2.7
9965
.9966
.9967
.9968
.9969
.9970
.9971
.9972
.9973
.9974
2.7
2.8
9974
.9975
.9976
.9977
.9977
.9978
.9979
.9979
.9980
.9981
2.8
2.9
.9981
9982
.9982
.9983
.9984
.9984
.9985
.9985
.9986
.9986
2.9
3.0
.9987
.9987
.9987
.9988
.9988
.9989
.9989
.9989
.9990
.9990
3.0
3.1
.9990
.9991
9991
.9991
.9992
.9992
.9992
.9992
.9993
.9993
3.1
3.2
.9993
.9993
.9994
.9994
.9994
.9994
9994
.9995
9995
9995
3.2
3.3
9995
9995
.9995
9996
9996
.9996
.9996
.9996
.9996
.9997
3.3
3.4
.9997
.9997
.9997
.9997
9997
.9997
,9997
.9997
.9997
.9998
3.4
3.50. and up
9999
3.50. and up
.00
05
.01
.02
03
.04
.06
.07
.08
.09
Standard Normal (z) Distribution: Cumulative Area from the LEFT

Expert Solution

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Proportions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.