**Using Sample Data and Confidence Levels for Estimation**In this exercise, we examine how to use sample data with a given confidence level to complete statistical estimations. The specific context involves a drug used to prevent blood clots, where among 4856 patients treated, 182 developed adverse reactions. We need to estimate the population proportion of adverse reactions.### Steps:a) **Best Point Estimate of the Population Proportion, \( p \):**To find the best point estimate, calculate the sample proportion:\[p = \frac{\text{Number of adverse reactions}}{\text{Total number of patients}} = \frac{182}{4856}\](Round to three decimal places as needed.)b) **Margin of Error, \( E \):**The margin of error is determined based on the chosen confidence level, typically involving a z-score for the desired confidence interval:\[E = z \times \sqrt{\frac{p(1-p)}{n}}\]where \( z \) is the z-score corresponding to the confidence level, \( p \) is the sample proportion, and \( n \) is the sample size.(Round to three decimal places as needed.)c) **Confidence Interval:**Construct the confidence interval for \( p \) using:\[(p - E) < p < (p + E)\](Round to three decimal places as needed.)d) **Interpretation of the Confidence Interval:**Choose the correct statement interpreting the confidence interval:- **A.** One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.- **B.** There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound.- **C.** 90% of sample proportions will fall between the lower bound and the upper bound.- **D.** One has 90% confidence that the sample proportion is equal to the population proportion.### Explanation:Choose **option A** because it accurately describes the basis of confidence intervals, indicating the level of confidence that the interval includes the true population proportion. The interpretation relies on the fact that if we were to take many samples and construct a confidence interval for each, approximately 90% of them would contain the true population proportion. In clinical trials, among 4856 patients treated with the drug, 182 developed the adverse reaction of nausea. Construct a 90% confidence interval. Choose the correct answer below.- From the lower bound to the upper bound actually does contain the true value of the population proportion.- The population proportion will fall between the lower bound and the upper bound.- Both the lower bound and the upper bound.- Exactly equal to the population proportion.

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4856 patients treated with the drug, 182 developed the a interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion.p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. ( E= (Round to three decimal places as needed.) c) Construct the confidence interval. 0

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4856 patients treated with the drug, 182 developed the a interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion.p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. ( E= (Round to three decimal places as needed.) c) Construct the confidence interval. 0

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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