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Use the References to access important values if needed for this question. What volume of a 0.274 M HI solution is required to neutralize 26.8 mL of a 0.121 M KOH solution? HI+KOH → KI + H₂O mL HI

Use the References to access important values if needed for this question. What volume of a 0.274 M HI solution is required to neutralize 26.8 mL of a 0.121 M KOH solution? HI+KOH → KI + H₂O mL HI

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I forgot the formula please any help would be appritiated
he teaching and lea X ignment/takeCovalentActivity.do?locator-assignment-take au... + FS Home | Lawson Stat... [Review Topics] [References] Use the References to access important values if needed for this question. What volume of a 0.274 M HI solution is required to neutralize 26.8 mL of a 0.121 M KOH solution? HI+KOH → KI + H₂O mL HI Submit Answer Retry Entire Group DELL F8 3 more group attempts remaining F10 F11 F12 PrtScr Insert D
Transcribed Image Text:he teaching and lea X ignment/takeCovalentActivity.do?locator-assignment-take au... + FS Home | Lawson Stat... [Review Topics] [References] Use the References to access important values if needed for this question. What volume of a 0.274 M HI solution is required to neutralize 26.8 mL of a 0.121 M KOH solution? HI+KOH → KI + H₂O mL HI Submit Answer Retry Entire Group DELL F8 3 more group attempts remaining F10 F11 F12 PrtScr Insert D
Expert Solution
Step 1

Potassium hydroxide reacts with hydroiodic acid, to form potassium iodide and water. The equation for the balanced chemical reaction is as follows:

HI  +  KOH   →  KI + 2H2O

The stoichiometry of the balanced chemical reaction states that one mole of base reacts with one mole of acid to form one mole of salt and one mole of water.

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