Use the References to access important values if needed for this question. The nonvolatile, nonelectrolyte antifreeze (ethylene glycol), CH₂OHCH₂OH (62.10 g/mol), is soluble in water, H₂O. Calculate the osmotic pressure generated when 13.5 grams of antifreeze are dissolved in water to form 227 mL of solution at 298 K. The molarity of the solution is M. The osmotic pressure of the solution is Submit Answer Retry Entire Group torr. 3 more group attempts remaining
Use the References to access important values if needed for this question. The nonvolatile, nonelectrolyte antifreeze (ethylene glycol), CH₂OHCH₂OH (62.10 g/mol), is soluble in water, H₂O. Calculate the osmotic pressure generated when 13.5 grams of antifreeze are dissolved in water to form 227 mL of solution at 298 K. The molarity of the solution is M. The osmotic pressure of the solution is Submit Answer Retry Entire Group torr. 3 more group attempts remaining
Chemistry
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ISBN:9781305957404
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:2req
M
M
2req
The nonvolatile, nonelectrolyte antifreeze (ethylene glycol), CH₂OHCH₂OH (62.10 g/mol),
is soluble in water, H₂O. Calculate the osmotic pressure generated when 13.5 grams of
antifreeze are dissolved in water to form 227 mL of solution at 298 K.
The molarity of the solution is
M.
The osmotic pressure of the solution is
Submit Answer
R
[Review Topics)
(References)
Use the References to access important values if needed for this question.
H
Retry Entire Group
QL DCH
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B
DELL
H
N
3 more group attempts remaining
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8
M
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Expert Solution
Step 1
Molecular weight of Ethylene glycol = 62.10 g/mol
Mass of Ethylene glycol= 13.5 g
Number of moles of Ethylene glycol= mass/mol.wt.
= 13.5 g/(62.10 g/mol) = 0.21739 mol
Volume of the solution = 277 mL = 0.277 L
Molarity of the solution = moles/volume = 0.21739 mol/ 0.277 L = 0.784806 M
Molarity of the solution = 0.785 M
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