Use the References to access important values if needed for this question. a. How many ATOMS of nitrogen are present in 2.50 moles of nitrogen dioxide? 1.505x10^24 atoms of nitrogen b. How many MOLES of oxygen are present in 1.08 × 1023 molecules of nitrogen dioxide? moles of oxygen 2

World of Chemistry, 3rd edition
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Chapter6: Chemical Composition
Section: Chapter Questions
Problem 17A
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**Question:**  
Use the References to access important values if needed for this question.

a. How many ATOMS of nitrogen are present in 2.50 moles of nitrogen dioxide?

**Answer:**  
\( 1.505 \times 10^{24} \) atoms of nitrogen

b. How many MOLES of oxygen are present in \(1.08 \times 10^{23}\) molecules of nitrogen dioxide?

**Answer:**  
2 moles of oxygen
Transcribed Image Text:**Question:** Use the References to access important values if needed for this question. a. How many ATOMS of nitrogen are present in 2.50 moles of nitrogen dioxide? **Answer:** \( 1.505 \times 10^{24} \) atoms of nitrogen b. How many MOLES of oxygen are present in \(1.08 \times 10^{23}\) molecules of nitrogen dioxide? **Answer:** 2 moles of oxygen
### Determining the Sample with the Greatest Number of Atoms

To solve the following problem, you may need to refer to reference materials for important values.

**Problem Statement:**

**Question**: Which sample contains the greatest number of atoms: A sample of Germanium (Ge) that contains \(1.97 \times 10^{24}\) atoms or a 6.28 mole sample of Krypton (Kr)?

**Conclusion**:
The sample of [Blank] contains the greatest number of atoms.

**Explanation:**

- To determine which sample contains the greatest number of atoms, you can compare the given quantity of atoms directly to the quantity converted from moles.

- For Krypton (Kr), we need to convert the amount given in moles to the number of atoms. We use Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole):

\[ 
\text{Number of atoms in 6.28 moles of Kr} = 6.28 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} 
\]

- Calculate this quantity to compare it with the given number of atoms in the Germanium (Ge) sample.

Complete the calculation and fill in the blank accordingly.
Transcribed Image Text:### Determining the Sample with the Greatest Number of Atoms To solve the following problem, you may need to refer to reference materials for important values. **Problem Statement:** **Question**: Which sample contains the greatest number of atoms: A sample of Germanium (Ge) that contains \(1.97 \times 10^{24}\) atoms or a 6.28 mole sample of Krypton (Kr)? **Conclusion**: The sample of [Blank] contains the greatest number of atoms. **Explanation:** - To determine which sample contains the greatest number of atoms, you can compare the given quantity of atoms directly to the quantity converted from moles. - For Krypton (Kr), we need to convert the amount given in moles to the number of atoms. We use Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole): \[ \text{Number of atoms in 6.28 moles of Kr} = 6.28 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} \] - Calculate this quantity to compare it with the given number of atoms in the Germanium (Ge) sample. Complete the calculation and fill in the blank accordingly.
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