Use the red wavelength of 650nm, assuming the ground state of the electron is energy level nf=2, calculate (ni). R=1.097 x 10^7 m-1 nf =2

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
Use the red wavelength of 650nm, assuming the ground state of the electron is energy level nf=2, calculate (ni). R=1.097 x 10^7 m-1 nf =2
The image presents a mathematical equation, which is structured as follows:

The variable \( n_i \) is defined by the expression:

\[
n_i = \sqrt{\frac{n_f^2 \lambda R}{\lambda R - n_f^2}}
\]

Here is the breakdown of the equation:

- \( n_i \) is the resultant variable on the left side of the equation.
- The right side of the equation features a square root.
- Inside the square root, the fraction denotes the division of two expressions:
  - The numerator is \( n_f^2 \lambda R \).
  - The denominator is \( \lambda R - n_f^2 \).

In this expression:
- \( n_f \) might represent a value such as a refractive index or another parameter in a scientific context, which is squared.
- \( \lambda \) and \( R \) are other parameters or constants that interact with \( n_f \) in the equation. 

This type of equation might be utilized in fields such as optics or physics to describe relationships involving refractive indices or wave properties.
Transcribed Image Text:The image presents a mathematical equation, which is structured as follows: The variable \( n_i \) is defined by the expression: \[ n_i = \sqrt{\frac{n_f^2 \lambda R}{\lambda R - n_f^2}} \] Here is the breakdown of the equation: - \( n_i \) is the resultant variable on the left side of the equation. - The right side of the equation features a square root. - Inside the square root, the fraction denotes the division of two expressions: - The numerator is \( n_f^2 \lambda R \). - The denominator is \( \lambda R - n_f^2 \). In this expression: - \( n_f \) might represent a value such as a refractive index or another parameter in a scientific context, which is squared. - \( \lambda \) and \( R \) are other parameters or constants that interact with \( n_f \) in the equation. This type of equation might be utilized in fields such as optics or physics to describe relationships involving refractive indices or wave properties.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Atomic Structure and Spectra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY