Use the quotient rule to find the derivative. x² + 8x +3 y= √x OA. dy 2x+8 dx X B. O C. dy dx dy dx 11 11 11 3x² +8x-3 2x3/2 3x² +8x-3 X OD. dy 2x+8 = 3/2 dx 2x ...
Use the quotient rule to find the derivative. x² + 8x +3 y= √x OA. dy 2x+8 dx X B. O C. dy dx dy dx 11 11 11 3x² +8x-3 2x3/2 3x² +8x-3 X OD. dy 2x+8 = 3/2 dx 2x ...
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![**Question:**
Use the quotient rule to find the derivative.
\[ y = \frac{x^2 + 8x + 3}{\sqrt{x}} \]
**Options:**
- **A.** \(\frac{dy}{dx} = \frac{2x + 8}{x}\)
- **B.** \(\frac{dy}{dx} = \frac{3x^2 + 8x - 3}{2x^{3/2}}\)
- **C.** \(\frac{dy}{dx} = \frac{3x^2 + 8x - 3}{x}\)
- **D.** \(\frac{dy}{dx} = \frac{2x + 8}{2x^{3/2}}\)
**Instructions:**
Select the correct derivative of the given function using the quotient rule.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae259756-8f06-4e5c-ae2d-b16c40451d6f%2F89447e04-ca64-4dd2-85fb-0a2758652c6d%2Faskh10i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
Use the quotient rule to find the derivative.
\[ y = \frac{x^2 + 8x + 3}{\sqrt{x}} \]
**Options:**
- **A.** \(\frac{dy}{dx} = \frac{2x + 8}{x}\)
- **B.** \(\frac{dy}{dx} = \frac{3x^2 + 8x - 3}{2x^{3/2}}\)
- **C.** \(\frac{dy}{dx} = \frac{3x^2 + 8x - 3}{x}\)
- **D.** \(\frac{dy}{dx} = \frac{2x + 8}{2x^{3/2}}\)
**Instructions:**
Select the correct derivative of the given function using the quotient rule.
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