Use the quadratic formula to find the two roots. Here is the quadratic formula: -b + Vb^2- 4ac/2a Show your work here: e. Substitute two roots, r1 and r2 into the equation an= a1r1^n+ a2r2^n Show your work here:     f. Now substitute to find two equations, a0 and a1 Remember to use the equation you found from step e. show your work here:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Parts (a), (b), (c) are solved. d,e,f,g,h,i needs to be solved

I also added all the photos.

 

(a) Given that, 

an= 6* an-1+ 7* an-2

Compare this equation with, 

an= c1 an-1 + c2* an-2

We get that, 

c1= 6 

and c2= 7

 

(b) r2-c1r-c2= 0

Put the value of c1 and c2 in the above equation, 

r2-6*r-7= 0



(c) a*r2*b*r+c= 0

a= 1

b= -6 

and c= -7 

 

 

 

d. Use the quadratic formula to find the two roots. Here is the quadratic formula:

-b + Vb^2- 4ac/2a

Show your work here:



e. Substitute two roots, r1 and r2 into the equation an= a1r1^n+ a2r2^n

Show your work here:

 

 

f. Now substitute to find two equations, a0 and a1 Remember to use the equation you found from step e.

show your work here:

a0= 3 =
a1= 6 =


g. Add the two equations together find a1 and a2 

a1= 

a2=

 

h. What is the solution to the recurrence relations?

an= 

 

i. Find the 10" term of the sequence, using the solution to the recurrence relation you just found.

Show your work here: 

a10= 

### Solving the Recurrence Relation

**Problem Statement:**
Solve the recurrence relation. Given:
- \( a_0 = 3 \)
- \( a_1 = 6 \)
- \( a_n = 6a_{n-1} + 7a_{n-2} \)

Show your work in the space provided.

**Steps:**

a. **Find \( c_1 \) and \( c_2 \):**

The recurrence relation can be expressed as:
\[ a_n = 6a_{n-1} + 7a_{n-2} \]

b. **Substitute \( c_1 \) and \( c_2 \) into the following equation:**
\[ r^2 - c_1 r - c_2 = 0 \]

- **Values to be determined:**
  - \( c_1 = \)
  - \( c_2 = \)

c. **Identify \( a \), \( b \), and \( c \) in the quadratic equation.**

- \( a = \)
- \( b = \)
- \( c = \)

d. **Use the quadratic formula to find the two roots.**

Here is the quadratic formula:
\[ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

- **Solution Steps:**
  - Substitute the values of \( a \), \( b \), and \( c \) to find the roots.
  - Work to be shown in the space provided.

---
**Note:** Use the provided space in your worksheet to perform calculations and derive the final result for \( r \).
Transcribed Image Text:### Solving the Recurrence Relation **Problem Statement:** Solve the recurrence relation. Given: - \( a_0 = 3 \) - \( a_1 = 6 \) - \( a_n = 6a_{n-1} + 7a_{n-2} \) Show your work in the space provided. **Steps:** a. **Find \( c_1 \) and \( c_2 \):** The recurrence relation can be expressed as: \[ a_n = 6a_{n-1} + 7a_{n-2} \] b. **Substitute \( c_1 \) and \( c_2 \) into the following equation:** \[ r^2 - c_1 r - c_2 = 0 \] - **Values to be determined:** - \( c_1 = \) - \( c_2 = \) c. **Identify \( a \), \( b \), and \( c \) in the quadratic equation.** - \( a = \) - \( b = \) - \( c = \) d. **Use the quadratic formula to find the two roots.** Here is the quadratic formula: \[ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] - **Solution Steps:** - Substitute the values of \( a \), \( b \), and \( c \) to find the roots. - Work to be shown in the space provided. --- **Note:** Use the provided space in your worksheet to perform calculations and derive the final result for \( r \).
**Text on Educational Website:**

---

**e.** Substitute two roots, \( r_1 \) and \( r_2 \), into the equation \( a_n = \alpha_1 r_1^n + \alpha_2 r_2^n \).

**Show your work here:**

[Blank box for student input]

---

**f.** Now substitute to find two equations, \( a_0 \) and \( a_1 \). Remember to use the equation you found from step e.

**Show your work here:**

\[ a_0 = 3 \]

\[ a_1 = 6 \]

[Blank box for student input]

---

**g.** Add the two equations together to find \( a_1 \) and \( a_2 \).

\[ a_1 = \]

\[ a_2 = \]

[Blank space for student input]

---

**h.** What is the solution to the recurrence relations?

\[ a_n = \]

[Blank space for student input]

---

**i.** Find the 10th term of the sequence, using the solution to the recurrence relation you just found.

**Show your work here:**

\[ a_{10} = \]

[Blank box for student input]

--- 

This set of instructions guides students through substituting roots into a recurrence relation, determining initial conditions, combining equations, and ultimately solving for specific terms in a sequence. Each step offers space for students to show their calculations and reasoning.
Transcribed Image Text:**Text on Educational Website:** --- **e.** Substitute two roots, \( r_1 \) and \( r_2 \), into the equation \( a_n = \alpha_1 r_1^n + \alpha_2 r_2^n \). **Show your work here:** [Blank box for student input] --- **f.** Now substitute to find two equations, \( a_0 \) and \( a_1 \). Remember to use the equation you found from step e. **Show your work here:** \[ a_0 = 3 \] \[ a_1 = 6 \] [Blank box for student input] --- **g.** Add the two equations together to find \( a_1 \) and \( a_2 \). \[ a_1 = \] \[ a_2 = \] [Blank space for student input] --- **h.** What is the solution to the recurrence relations? \[ a_n = \] [Blank space for student input] --- **i.** Find the 10th term of the sequence, using the solution to the recurrence relation you just found. **Show your work here:** \[ a_{10} = \] [Blank box for student input] --- This set of instructions guides students through substituting roots into a recurrence relation, determining initial conditions, combining equations, and ultimately solving for specific terms in a sequence. Each step offers space for students to show their calculations and reasoning.
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