Use the Product Rule or Quotient Rule to find the derivative of f(x) = O None of these. f'(x) = f'(x) = 12x³ - 4x -3 f'(x) = (5 – 3x) (12x³ — 4x) − (3x − 2x² + 1) (−3) (5 - 3x)² f'(x) = f'(x) = (3x4 - 2x² + 1) (-3) - (5-3x) (12x³ - 4x) (5 - 3x)² (5-3x) (12x³ - 4x) + (3x4 - 2x² + 1) (-3) (5-3x) (5-3x) (-3)-(3x4 ▬▬ a ■ - 2x² + 1) (12x³ - 4x) (5 - 3x)² D 3x4 - 2x² +1 5 - 3x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the Product Rule or Quotient Rule to find the derivative of f(x) =
O None of these.
ƒ'(x) =
ƒ'(x) =
12x³ - 4x
-3
f'(x) =
(5 – 3x) (12x³ — 4x) − (3x − 2x² + 1) (−3)
(5 - 3x)²
f'(x) =
f'(x) =
(3x4 - 2x² + 1) (-3) - (5 - 3x) (12x³ - 4x)
(5 - 3x)²
(5-3x) (12x³ - 4x) + (3x4 - 2x² + 1) (-3)
(5 - 3x)
(5-3x) (-3)-(3x4
L
—
a
■
- 2x² + 1) (12x³ - 4x)
(5 - 3x)²
i
3x4 - 2x² +1
5 - 3x
Transcribed Image Text:Use the Product Rule or Quotient Rule to find the derivative of f(x) = O None of these. ƒ'(x) = ƒ'(x) = 12x³ - 4x -3 f'(x) = (5 – 3x) (12x³ — 4x) − (3x − 2x² + 1) (−3) (5 - 3x)² f'(x) = f'(x) = (3x4 - 2x² + 1) (-3) - (5 - 3x) (12x³ - 4x) (5 - 3x)² (5-3x) (12x³ - 4x) + (3x4 - 2x² + 1) (-3) (5 - 3x) (5-3x) (-3)-(3x4 L — a ■ - 2x² + 1) (12x³ - 4x) (5 - 3x)² i 3x4 - 2x² +1 5 - 3x
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