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Use the parametrization r(x,z) = xi + f(x,z)j + zk and the following equation to derive a formula for do associated with the explicit form y = f(x,z). do = ru xr du dv (for r(u.v)) First recognize that u = x and v=z. Find rx (x.z). Choose the correct answer below. A. (x.z)=i+f₂(x,z)j OC. (x.z)=i+fx(x,z)j OE. x(x,z)=i+fx(x,z)j + zk OG. x(x,z)=i+ f(x.z)j www B. x(x,z)=xi +f₂(x,z)j + k (x.z)=f(x,z)j + k OD. OF. x(x,z)=f(x,z)j + k ⒸH. rx (x.z) = fx(x,z)j + k

Use the parametrization r(x,z) = xi + f(x,z)j + zk and the following equation to derive a formula for do associated with the explicit form y = f(x,z). do = ru xr du dv (for r(u.v)) First recognize that u = x and v=z. Find rx (x.z). Choose the correct answer below. A. (x.z)=i+f₂(x,z)j OC. (x.z)=i+fx(x,z)j OE. x(x,z)=i+fx(x,z)j + zk OG. x(x,z)=i+ f(x.z)j www B. x(x,z)=xi +f₂(x,z)j + k (x.z)=f(x,z)j + k OD. OF. x(x,z)=f(x,z)j + k ⒸH. rx (x.z) = fx(x,z)j + k

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the parametrization r(x,z) = xi + f(x,z)j + zk and the following equation to derive a formula for do associated with the explicit form y = f(x.z). do G=|r₁ xr₁| du dv (for r(u.v)) First recognize that u = x and v=z. Find rx (x.z). Choose the correct answer below. OA. (x.z)=i+f₂(x,z)j OC. x(x,z)=i+fx(x,z)j OE. x(x,z)=i+fx(x,z)j + zk O G. (x.z)=i+ f(x.z)j B. rx (x.z)=xi + f₂(x,z)j + k O D. x(x,z)=f₂(x.z)j + k OF. rx (x.z)=f(x,z)j + k ⒸH. x(x.z) = fx(x.z)j + k
Transcribed Image Text:Use the parametrization r(x,z) = xi + f(x,z)j + zk and the following equation to derive a formula for do associated with the explicit form y = f(x.z). do G=|r₁ xr₁| du dv (for r(u.v)) First recognize that u = x and v=z. Find rx (x.z). Choose the correct answer below. OA. (x.z)=i+f₂(x,z)j OC. x(x,z)=i+fx(x,z)j OE. x(x,z)=i+fx(x,z)j + zk O G. (x.z)=i+ f(x.z)j B. rx (x.z)=xi + f₂(x,z)j + k O D. x(x,z)=f₂(x.z)j + k OF. rx (x.z)=f(x,z)j + k ⒸH. x(x.z) = fx(x.z)j + k
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