Use the number-line model to show that 6( 3) = 18. Choose the correct answer below. O A. to to -20-19(-18-17-16-15-14-13-12-11-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 O B. 十+ -20-19(18-17-16-15-14-13-12-11-10 -9 -8 -7 -6 -5 -4 -3-2-1 0 1 OC. 十十+ + -1 0 十+ 10 11 12 13 14 15 16 17 3. 4. 5. 6. 8 9. 18) 19 O D. 十++ -1 0 12 4. 5. 9. 7. 9 10 11 12 13 14 15 16 17 (18 19 ++

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
icon
Related questions
Question
Use the number-line model to show that 6 (-3) = -18
**Using the Number-Line Model to Show \(6 \times (-3) = -18\)**

**Question:**
Use the number-line model to show that \(6 \times (-3) = -18\).

Choose the correct answer below.

**Options:**

- **A.**

  A number line ranging from -20 to 1. Starting at 0, there are six jumps to the left, each of three units, marked by red arrows. The final arrow points to -18, which is circled.

- **B.**

  A number line ranging from -20 to 1. Starting at 0, there are six jumps to the left, each of three units, marked by blue arrows. The final arrow points to -18, which is circled.

- **C.**

  A number line ranging from -1 to 19. Starting at 0, there are six jumps to the right, each of three units, marked by blue arrows. The final arrow points to 18, which is circled.

- **D.**

  A number line ranging from -1 to 19. Starting at 0, there are six jumps to the right, each of three units, marked by red arrows. The final arrow points to 18, which is circled.

**Explanation:**

Option A correctly demonstrates the equation \(6 \times (-3) = -18\) on the number line by showing six leftward jumps (each of three units) starting from 0, ending at -18.
Transcribed Image Text:**Using the Number-Line Model to Show \(6 \times (-3) = -18\)** **Question:** Use the number-line model to show that \(6 \times (-3) = -18\). Choose the correct answer below. **Options:** - **A.** A number line ranging from -20 to 1. Starting at 0, there are six jumps to the left, each of three units, marked by red arrows. The final arrow points to -18, which is circled. - **B.** A number line ranging from -20 to 1. Starting at 0, there are six jumps to the left, each of three units, marked by blue arrows. The final arrow points to -18, which is circled. - **C.** A number line ranging from -1 to 19. Starting at 0, there are six jumps to the right, each of three units, marked by blue arrows. The final arrow points to 18, which is circled. - **D.** A number line ranging from -1 to 19. Starting at 0, there are six jumps to the right, each of three units, marked by red arrows. The final arrow points to 18, which is circled. **Explanation:** Option A correctly demonstrates the equation \(6 \times (-3) = -18\) on the number line by showing six leftward jumps (each of three units) starting from 0, ending at -18.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON
Contemporary Abstract Algebra
Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON
Introduction to Linear Algebra, Fifth Edition
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press
College Algebra (Collegiate Math)
College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education