Use the normal distribution calculator to calculate the p-value. Calculator z=:P(Z szIn a hypothesis test with hypotheses Ho: ≤ 50 and H₁ μ> 50, a random sample of 125 elements selected from the populationproduced a mean of 55.6. Assume that = 23.5, and that the test is to be made at the 3% significance level.What is the p-value for this hypothesis test, rounded to three decimal places?e Texthook and Media

Given,Hypotheses are-Sample size, n = 125Sample mean, = 55.6Population standard deviation, σ = 23.5

Answered: Use the normal distribution calculator…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that the sample average is 44.4 while the null hypothesis is that the population mean is 44. If the standard error is 1 then what is the t test statistic? (Answer to 4 decimal places if necessary).
The test statistic of z = 2.47 is obtained when testing the claim that p > 0.8. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of a = 0.05, should we reject Ho or should we fail to reject Ho? A. Fail to reject Ho. There is not sufficient evidence to support the claim that p > 0.8. B. Reject Ho. There is not sufficient evidence to support the claim that p > 0.8 C. Fail to reject Ho. There is sufficient evidence to support the claim that p > 0.8. D. Reject Ho. There is sufficient evidence to support the claim that p > 0.8.
Test the claim that the mean GPA of night students is smaller than 2.5 at the .05 significance level.The null and alternative hypothesis would be: H0:p=0.625H0:p=0.625H1:p>0.625H1:p>0.625 H0:p=0.625H0:p=0.625H1:p<0.625H1:p<0.625 H0:μ=2.5H0:μ=2.5H1:μ≠2.5H1:μ≠2.5 H0:p=0.625H0:p=0.625H1:p≠0.625H1:p≠0.625 H0:μ=2.5H0:μ=2.5H1:μ>2.5H1:μ>2.5 H0:μ=2.5H0:μ=2.5H1:μ<2.5H1:μ<2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 55 people, the sample mean GPA was 2.49 with a standard deviation of 0.05The test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
The recidivism rate for convicted sex offenders is 13%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 309 convicted sex offenders who were also drug addicts, 31 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is ? va Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 13% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
The test statistic of z = 0.53 is obtained when testing the claim that p > 0.5. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of α = 0.05, should we reject H0 or should we fail to reject H0?
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z=1.95. A. 0.9744; fail to reject the null hypothesis B. 0.0512; fail to reject the null hypothesis C. 0.0512; reject the null hypothesis D. 0.0256; reject the null hypothesis
I
If the p-value of a hypothesis test is equal to 0.035, then the null hypothesis will be rejected for which cases? SELECT ALL THAT APPLY. a. for a significance level of 0.01 b. for a significance level of 0.10 c. for a significance level of 0.05 d. for a significance level of 0.02
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Test the claim that the mean GPA of night students is smaller than 3.3 at the 0.10 significance level. The null and alternative hypothesis would be: Ho:p 0.825 Ho:p ≤ 0.825 Ho: ≤3.3 Ho: 3.3 Ho: 23.3 Ho:p> 0.825 H₁:p0.825 H₁:p> 0.825 H₁:p>3.3 H₁: 3.3 H₁: <3.3 H₁ p < 0.825 O The test is: right-tailed left-tailed two-tailed Based on a sample of 65 people, the sample mean GPA was 3.26 with a standard deviation of 0.02 The test statistic is: (to 2 decimals) The p-value is: Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis (to 2 decimals)
Suppose that your 95% confidence interval for p is (0.68, 0.74). Based on the confidence interval what would your decision be for the hypothesis test H0: p=0.8 versus H1:p≠0.8 at the α=0.05 level?

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