Use the norm map N: Z [√-3] → Z2o by N(a+b√-3) = a² + 36² (you can assume it is multiplicative, i.e N(wz) = N(w)N(z)) to prove (a) The only units of Z [√-3] are +1 (b) Z[√-3] is not a UFD in two ways: (i) by producing an irreducible element that isn't prime and showing the uniqueness into irreducibles is violated in this ring (like we did for Z [√5] )

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Use the norm map N: Z [√-3] → Z2o by N(a+b√-3) = a² + 36² (you
can assume it is multiplicative, i.e N(wz) = N(w)N(z)) to prove
(a) The only units of Z [√-3] are ±1
(b) Z[√-3] is not a UFD in two ways: (i) by producing an irreducible
element that isn't prime and showing the uniqueness into irreducibles
is violated in this ring (like we did for Z [√5] )
Transcribed Image Text:Use the norm map N: Z [√-3] → Z2o by N(a+b√-3) = a² + 36² (you can assume it is multiplicative, i.e N(wz) = N(w)N(z)) to prove (a) The only units of Z [√-3] are ±1 (b) Z[√-3] is not a UFD in two ways: (i) by producing an irreducible element that isn't prime and showing the uniqueness into irreducibles is violated in this ring (like we did for Z [√5] )
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