Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x, y) whose differential, dF(x, y) gives the differential equation. That is, level curves F(x, y) = C are solutions to the differential equation: %3D dy 4x3 – 2y dx 2x – 2y2 First rewrite as M(x, y) dx + N(x, y) dy = 0 where M(x, y) 4x^3-2y and N(x, y) = -2x+2y^2 If the equation is not exact, enter not exact, otherwise enter in F(x, y) as the solution of the differential equation here = C.
Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x, y) whose differential, dF(x, y) gives the differential equation. That is, level curves F(x, y) = C are solutions to the differential equation: %3D dy 4x3 – 2y dx 2x – 2y2 First rewrite as M(x, y) dx + N(x, y) dy = 0 where M(x, y) 4x^3-2y and N(x, y) = -2x+2y^2 If the equation is not exact, enter not exact, otherwise enter in F(x, y) as the solution of the differential equation here = C.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Need the last part aka the solution to the differential equation
Transcribed Image Text:Use the "mixed partials" check to see
if the following differential equation is exact.
If it is exact find a function F(x, y) whose
differential, dF(x, y) gives the differential
equation. That is, level curves F(x,y) = C are
solutions to the differential equation:
dy
4x3
2y
dx
2x – 2y2
First rewrite as
М(х, у) dx + N(х, у) dy %3D 0
where M(x, y)
4x^3-2y
and N(x, y) = -2x+2y^2
If the equation is not exact, enter not exact,
otherwise enter in F(x, y) as the solution of the
differential equation here
= C.
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