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Therefore, from the above solution we can conclude that : x(t) = 10 He³ 3t e³t - 1.6 [៦] e -t -8.4e2t + -2e2t Use the method of variation of parameters to solve the initial value problem x' = Ax+f(t), x(a)=x using the following values. 4 -1 8 A= 16 |, f(t) = 7 1 + 4t x(0) = eAt -t = - 4 16t 1-4t x(t)= = ...

Therefore, from the above solution we can conclude that : x(t) = 10 He³ 3t e³t - 1.6 [៦] e -t -8.4e2t + -2e2t Use the method of variation of parameters to solve the initial value problem x' = Ax+f(t), x(a)=x using the following values. 4 -1 8 A= 16 |, f(t) = 7 1 + 4t x(0) = eAt -t = - 4 16t 1-4t x(t)= = ...

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Therefore, from the above solution we can conclude that : x(t) = 10 He³ 3t e³t - 1.6 [៦] e -t -8.4e2t + -2e2t
Transcribed Image Text:Therefore, from the above solution we can conclude that : x(t) = 10 He³ 3t e³t - 1.6 [៦] e -t -8.4e2t + -2e2t
Use the method of variation of parameters to solve the initial value problem x' = Ax+f(t), x(a)=x using the following values. 4 -1 8 A= 16 |, f(t) = 7 1 + 4t x(0) = eAt -t = - 4 16t 1-4t x(t)= = ...
Transcribed Image Text:Use the method of variation of parameters to solve the initial value problem x' = Ax+f(t), x(a)=x using the following values. 4 -1 8 A= 16 |, f(t) = 7 1 + 4t x(0) = eAt -t = - 4 16t 1-4t x(t)= = ...
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