Use the method of partial fractions to evaluate each of the following integral. dx Jalx – 1)(x – 2)(x – 3) 1) In|1– x| -in|2 – x| +ln[3 – x] -in|x + 2) 을m1-지-3미2-지 -jm3-지-jm지 +C 3) 를미1-지-3 m2 -지 +승m3-지 +능m지 + C 4) 111-지+1m2-지 +승m3-지-jim지 +c
Use the method of partial fractions to evaluate each of the following integral. dx Jalx – 1)(x – 2)(x – 3) 1) In|1– x| -in|2 – x| +ln[3 – x] -in|x + 2) 을m1-지-3미2-지 -jm3-지-jm지 +C 3) 를미1-지-3 m2 -지 +승m3-지 +능m지 + C 4) 111-지+1m2-지 +승m3-지-jim지 +c
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
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### Use the method of partial fractions to evaluate each of the following integral.
\[ \int \frac{x \, dx}{x(x-1)(x-2)(x-3)} \]
### Options:
1) \[\frac{1}{2} \ln|1 - x| - \frac{1}{2} \ln|2 - x| + \frac{1}{6} \ln|3 - x| - \frac{1}{6} \ln|x| + C\]
2) \[\frac{1}{2} \ln|1 - x| - \frac{1}{2} \ln|2 - x| - \frac{1}{6} \ln|3 - x| - \frac{1}{6} \ln|x| + C\]
3) \[\frac{1}{2} \ln|1 - x| - \frac{1}{2} \ln|2 - x| + \frac{1}{6} \ln|3 - x| + \frac{1}{6} \ln|x| + C\]
4) \[\frac{1}{2} \ln|1 - x| + \frac{1}{2} \ln|2 - x| + \frac{1}{6} \ln|3 - x| - \frac{1}{6} \ln|x| + C\]
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To solve the integral using the method of partial fractions, you would decompose the integrand into simpler fractions whose integrals are easier to evaluate. Then, using logarithmic properties, you can combine the results into a single expression plus a constant of integration, \(C\). Each option represents a potential solution to this integral.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30c07f2b-13db-4887-9bcb-8633a00a882e%2F2bfd0706-30e5-4459-8ddc-b6933debe33c%2Fnj5ipi7_processed.png&w=3840&q=75)
Transcribed Image Text:---
### Use the method of partial fractions to evaluate each of the following integral.
\[ \int \frac{x \, dx}{x(x-1)(x-2)(x-3)} \]
### Options:
1) \[\frac{1}{2} \ln|1 - x| - \frac{1}{2} \ln|2 - x| + \frac{1}{6} \ln|3 - x| - \frac{1}{6} \ln|x| + C\]
2) \[\frac{1}{2} \ln|1 - x| - \frac{1}{2} \ln|2 - x| - \frac{1}{6} \ln|3 - x| - \frac{1}{6} \ln|x| + C\]
3) \[\frac{1}{2} \ln|1 - x| - \frac{1}{2} \ln|2 - x| + \frac{1}{6} \ln|3 - x| + \frac{1}{6} \ln|x| + C\]
4) \[\frac{1}{2} \ln|1 - x| + \frac{1}{2} \ln|2 - x| + \frac{1}{6} \ln|3 - x| - \frac{1}{6} \ln|x| + C\]
---
To solve the integral using the method of partial fractions, you would decompose the integrand into simpler fractions whose integrals are easier to evaluate. Then, using logarithmic properties, you can combine the results into a single expression plus a constant of integration, \(C\). Each option represents a potential solution to this integral.
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