Use the method of Laplace transforms to solve the given initial value problem. Here, x' and y' denote differentiation with respect to t. x' - x - y = 1 -x+y'-y = 0 x(0) = 0 y(0)= 72 Click the icon to view information on Laplace transforms.

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### Solving Initial Value Problems Using Laplace Transforms

#### Problem Statement
Use the method of Laplace transforms to solve the given initial value problem. Here, x′ and y′ denote differentiation with respect to \( t \).

\[
\begin{aligned}
x' - x - y &= 1 \quad & x(0) = 0 \\
-x + y' - y &= 0 \quad & y(0) = -\frac{7}{2}
\end{aligned}
\]

#### Instructions
Click the icon to view information on Laplace transforms.

---

#### Solution

Fill in the exact answers in terms of \( e \):

\[
x(t) = \boxed{\phantom{a}}
\]
\[
y(t) = \boxed{\phantom{a}}
\]

(Type exact answers in terms of \( e \).)

---

This problem involves finding functions \( x(t) \) and \( y(t) \) that satisfy both the differential equations and the provided initial conditions. The Laplace transform is a powerful tool for solving such linear differential equations by converting them into algebraic equations in the Laplace domain.
Transcribed Image Text:### Solving Initial Value Problems Using Laplace Transforms #### Problem Statement Use the method of Laplace transforms to solve the given initial value problem. Here, x′ and y′ denote differentiation with respect to \( t \). \[ \begin{aligned} x' - x - y &= 1 \quad & x(0) = 0 \\ -x + y' - y &= 0 \quad & y(0) = -\frac{7}{2} \end{aligned} \] #### Instructions Click the icon to view information on Laplace transforms. --- #### Solution Fill in the exact answers in terms of \( e \): \[ x(t) = \boxed{\phantom{a}} \] \[ y(t) = \boxed{\phantom{a}} \] (Type exact answers in terms of \( e \).) --- This problem involves finding functions \( x(t) \) and \( y(t) \) that satisfy both the differential equations and the provided initial conditions. The Laplace transform is a powerful tool for solving such linear differential equations by converting them into algebraic equations in the Laplace domain.
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