Use the limit definition of the derivative to find a formula for f'(x) if f(x) = (g(x))², assuming that g is differentiable for all x. (Note: Your answer will be in terms of g(x) and g'(x). Do NOT use the Chain Rule in this case.) Assume that f(x) = (g(x))², where g(2) = -3 and g'(2) = 4. Using your answer from (a), find the equation of the line tangent to y = f(x) at x = 2.
Use the limit definition of the derivative to find a formula for f'(x) if f(x) = (g(x))², assuming that g is differentiable for all x. (Note: Your answer will be in terms of g(x) and g'(x). Do NOT use the Chain Rule in this case.) Assume that f(x) = (g(x))², where g(2) = -3 and g'(2) = 4. Using your answer from (a), find the equation of the line tangent to y = f(x) at x = 2.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Problem Statement:**
Use the **limit definition of the derivative** to find a formula for \( f'(x) \) if \( f(x) = (g(x))^2 \), assuming that \( g \) is differentiable for all \( x \). *(Note: Your answer will be in terms of \( g(x) \) and \( g'(x) \). Do NOT use the Chain Rule in this case.)*
---
**Part (b):**
Assume that \( f(x) = (g(x))^2 \), where \( g(2) = -3 \) and \( g'(2) = 4 \). Using your answer from (a), find the equation of the line tangent to \( y = f(x) \) at \( x = 2 \).
---
*Explanation for Educational Use:*
1. **Limit Definition of the Derivative:** This is a fundamental aspect of calculus used to determine the derivative of a function. It is defined as:
\[
f'(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}
\]
2. **Given Function Analysis:** The function \( f(x) = (g(x))^2 \) suggests a function composition where \( f \) depends on another function \( g(x) \).
3. **Finding the Derivative Using the Limit Definition:**
- First, substitute \( f(x) \) into the limit definition:
\[
f'(x) = \lim_{{h \to 0}} \frac{(g(x+h))^2 - (g(x))^2}{h}
\]
- Recognize the numerator as a difference of squares:
\[
(g(x+h))^2 - (g(x))^2 = (g(x+h) - g(x))(g(x+h) + g(x))
\]
- Substitute this back into the limit:
\[
f'(x) = \lim_{{h \to 0}} \frac{(g(x+h) - g(x))(g(x+h) + g(x))}{h}
\]
- Apply the limit to \( g(x+h) - g(x) \), using the fact that \( g \) is differentiable:
\[
f'(x) = g'(x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa360717a-76bf-4995-bb1b-bd6b8528dd67%2F86a0bd4a-f299-4d4b-abe7-a03e4922bf86%2Flab4l8c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Use the **limit definition of the derivative** to find a formula for \( f'(x) \) if \( f(x) = (g(x))^2 \), assuming that \( g \) is differentiable for all \( x \). *(Note: Your answer will be in terms of \( g(x) \) and \( g'(x) \). Do NOT use the Chain Rule in this case.)*
---
**Part (b):**
Assume that \( f(x) = (g(x))^2 \), where \( g(2) = -3 \) and \( g'(2) = 4 \). Using your answer from (a), find the equation of the line tangent to \( y = f(x) \) at \( x = 2 \).
---
*Explanation for Educational Use:*
1. **Limit Definition of the Derivative:** This is a fundamental aspect of calculus used to determine the derivative of a function. It is defined as:
\[
f'(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}
\]
2. **Given Function Analysis:** The function \( f(x) = (g(x))^2 \) suggests a function composition where \( f \) depends on another function \( g(x) \).
3. **Finding the Derivative Using the Limit Definition:**
- First, substitute \( f(x) \) into the limit definition:
\[
f'(x) = \lim_{{h \to 0}} \frac{(g(x+h))^2 - (g(x))^2}{h}
\]
- Recognize the numerator as a difference of squares:
\[
(g(x+h))^2 - (g(x))^2 = (g(x+h) - g(x))(g(x+h) + g(x))
\]
- Substitute this back into the limit:
\[
f'(x) = \lim_{{h \to 0}} \frac{(g(x+h) - g(x))(g(x+h) + g(x))}{h}
\]
- Apply the limit to \( g(x+h) - g(x) \), using the fact that \( g \) is differentiable:
\[
f'(x) = g'(x
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