use the Limit Comparison Test to prove convergence or divergence of the infinite series

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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use the Limit Comparison Test to prove convergence or divergence of the infinite series.

Certainly! Here is the transcription of the mathematical expression shown in the image:

---

### Problem 41

Evaluate the series:

\[ \sum_{n=3}^{\infty} \frac{3n + 5}{n(n - 1)(n - 2)} \]

---

This expression represents an infinite series that starts at \( n = 3 \) and sums infinitely. The general term of the series is given by:

\[ \frac{3n + 5}{n(n - 1)(n - 2)} \]

Where:
- The summation index \( n \) starts at 3.
- The numerator of the general term is \( 3n + 5 \).
- The denominator of the general term is the product of \( n \), \( (n - 1) \), and \( (n - 2) \).
Transcribed Image Text:Certainly! Here is the transcription of the mathematical expression shown in the image: --- ### Problem 41 Evaluate the series: \[ \sum_{n=3}^{\infty} \frac{3n + 5}{n(n - 1)(n - 2)} \] --- This expression represents an infinite series that starts at \( n = 3 \) and sums infinitely. The general term of the series is given by: \[ \frac{3n + 5}{n(n - 1)(n - 2)} \] Where: - The summation index \( n \) starts at 3. - The numerator of the general term is \( 3n + 5 \). - The denominator of the general term is the product of \( n \), \( (n - 1) \), and \( (n - 2) \).
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