Use the Laplace transform to solve the given initial-value problem. y" +y = 0(t-) + (t - 피, y(0) = 0, y'(0) = 0 2 5n y(t) = ( -cos(1) CoS t 2 2 Need Help? Read It
Use the Laplace transform to solve the given initial-value problem. y" +y = 0(t-) + (t - 피, y(0) = 0, y'(0) = 0 2 5n y(t) = ( -cos(1) CoS t 2 2 Need Help? Read It
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Hello!
Can you please explain how I should simplify this expression correctly? I am not sure what value belongs in the second box.
Thank you for your assistance.
![**Use the Laplace transform to solve the given initial-value problem.**
Given:
\[ y'' + y = \delta\left( t - \frac{1}{2} \pi \right) + \delta\left( t - \frac{5}{2} \pi \right), \quad y(0) = 0, \, y'(0) = 0 \]
Solution:
\[ y(t) = \left( -\cos(t) \right) u\left( t - \frac{\pi}{2} \right) + \cos\left( t - \frac{5\pi}{2} \right) u\left( t - \frac{5\pi}{2} \right) \]
There are two parts of the solution:
1. \( -\cos(t) \) multiplied by the unit step function \( u\left( t - \frac{\pi}{2} \right) \)
- This represents a step function that shifts the cosine function starting at \( t = \frac{\pi}{2} \).
2. \( \cos\left( t - \frac{5\pi}{2} \right) \) multiplied by the unit step function \( u\left( t - \frac{5\pi}{2} \right) \)
- This starts the cosine function at \( t = \frac{5\pi}{2} \).
**Need Help?**
If you require additional understanding or guidance on the concept, consider utilizing the assistance feature available.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c8a2351-0faf-49df-b50e-203220f7d5bc%2Ff67408dc-1b7b-4b37-9b18-0f772dbb0223%2Fsx14fa_processed.png&w=3840&q=75)
Transcribed Image Text:**Use the Laplace transform to solve the given initial-value problem.**
Given:
\[ y'' + y = \delta\left( t - \frac{1}{2} \pi \right) + \delta\left( t - \frac{5}{2} \pi \right), \quad y(0) = 0, \, y'(0) = 0 \]
Solution:
\[ y(t) = \left( -\cos(t) \right) u\left( t - \frac{\pi}{2} \right) + \cos\left( t - \frac{5\pi}{2} \right) u\left( t - \frac{5\pi}{2} \right) \]
There are two parts of the solution:
1. \( -\cos(t) \) multiplied by the unit step function \( u\left( t - \frac{\pi}{2} \right) \)
- This represents a step function that shifts the cosine function starting at \( t = \frac{\pi}{2} \).
2. \( \cos\left( t - \frac{5\pi}{2} \right) \) multiplied by the unit step function \( u\left( t - \frac{5\pi}{2} \right) \)
- This starts the cosine function at \( t = \frac{5\pi}{2} \).
**Need Help?**
If you require additional understanding or guidance on the concept, consider utilizing the assistance feature available.
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