Use the Jacobi method to find approximate solutions to 3x110x2 - 4x3 = 9 20x1 + 2x2 + 3x3 = 25 2x12 + 5x3 = 6 starting the initial values ₁ = 1, 2 = 1 ,and x3 = 1.2 and iterating until error is less than 2%. Round-off intermediate computed values to 7 decimal places and the answer to 5 decimal places. Reminder: Arrange the system to be Diagonally Dominant before iteration.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Use the Jacobi method to find approximate solutions to
3x110x24x3 = 9
20x1 + 2x2 + 3x3 = 25
2x1x2 + 5x3 = 6
starting the initial values 1 = 1,2 = 1,and x3 = 1.2 and iterating until error is less than 2%.
Round-off intermediate computed values to 7 decimal places and the answer to 5 decimal places.
Reminder: Arrange the system to be Diagonally Dominant before iteration.
O x1 =0.99789, x2 -1.00353, x3 =1.00476
X1 -0.99893, X2=1.00254, x3 =1.00155
O x1 =1.00092, x2 -0.99867, x3 =0.99761
O x₁ =1.00022, x2 -0.99960, x3 =0.99956
O none of the choices
Transcribed Image Text:Use the Jacobi method to find approximate solutions to 3x110x24x3 = 9 20x1 + 2x2 + 3x3 = 25 2x1x2 + 5x3 = 6 starting the initial values 1 = 1,2 = 1,and x3 = 1.2 and iterating until error is less than 2%. Round-off intermediate computed values to 7 decimal places and the answer to 5 decimal places. Reminder: Arrange the system to be Diagonally Dominant before iteration. O x1 =0.99789, x2 -1.00353, x3 =1.00476 X1 -0.99893, X2=1.00254, x3 =1.00155 O x1 =1.00092, x2 -0.99867, x3 =0.99761 O x₁ =1.00022, x2 -0.99960, x3 =0.99956 O none of the choices
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