Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. +x-5= 0, (1,2) f(x)=x+x-5 is ---Select--- on the closed interval [1, 2], f(1) = equation x4+x - 5 = 0 in the interval (1, 2). and f(2)= Since-3 < ?< 13, there is a number c in (1, 2) such that f(c) = ? by the Intermediate Value Theorem. Thus, there is a [---Select--- of the

Q: n=9,p=0.3x<3

A: Given: A binomial trial with n=9, p=0.3. The probability of binomial experiment is given as…

Q: 7/3+4/5+1/3=

A: Given: 73+45+13 To find: We have to calculate the value.

Q: -7/27+ 13/27

A: Calculation:Simplify the given expression as follows,

Q: 7/13p=-14/11

A:

Q: 60 27 2. + $6

A:

Q: Express n = 5 · 13 · 29 = a? + b² using at least three distinct pairs (a, b) E N x N.

A:

Q: 1 1 dx 3 5 x +x4

A:

Q: Evaluate L{r³e3+5,

A:

Q: 0 1 2 4 0 0 1 3

A:

Q: 6/7-2/3

A: our objective is to find the difference.

Q: 13. 13. Solve for x. 14.

A: Here we have to find the value of x .

Q: 3/4 5/6

A: The given set of questions ,  1 13÷16 Apply division rule ,  1316=13×61         =2 2 25÷47 Apply…

Q: (24 – 18) + (20 – 16) – -

A: Simplify  (24-18)+(20-16)

Q: .2 dz 2–1

A:

Q: 6/9 +  5/18 + 1 3/6

A:

Q: 5 1/6 - 2 1/3

A: Given that 5 1/6 - 2 1/3

Q: Let A = 2 0 and 1 -1 2 3. find A+(28)"

A: Given that A= 1201-12        and B=2-11103 find A+2BT

Q: 3573.48 The 3 in the ones place is times the value of the 3 in the thousands place. - a. 1000 b.…

A: Given:        Value =3573.48 The place value of all digits of given number.     1. The place value…

Q: 1/5 + 1/10 + 1/15

A: Sum of numbers

Q: n-5/6 + n+3/7 = 11/21

A: The given expression is

Q: n-3/4+n+5/7=5/14

A: Given:

Q: 6 3/20 - 6 3/8

A:

Q: 1/3+4/5=

A:

Q: 243 30

A:

Q: -5/9 + 1/2

A: The given expression is

Q: -5/8 + 1/10 + 3/4

A:

Q: n=9, p=0.2x<3

A: Here we need to find P(X&lt;3).

Q: 5+5/6=1/3x-1

A: Consider the given equation 5+56=13x-1

Q: 5/6=c/9

A: Given 56=c9 We want to calculate c

Q: 1/4 + 1/2 + 3/8 =

A: We need to find sum.