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Use the information provided to write the general conic form equation of each hyperbola. 8) Vertices: (6, 18), (6, 2) Endpoints of Conjugate Axis: (14, 10) (-2, 10) A) -x² + y² - 12x + 20y = 0 B) -x² + y² - 20x - 12y - 128 = 0 C) −x² + y² + 12x - 20y = 0 D) x² - y² - 12x + 20y - 128 = 0

Use the information provided to write the general conic form equation of each hyperbola. 8) Vertices: (6, 18), (6, 2) Endpoints of Conjugate Axis: (14, 10) (-2, 10) A) -x² + y² - 12x + 20y = 0 B) -x² + y² - 20x - 12y - 128 = 0 C) −x² + y² + 12x - 20y = 0 D) x² - y² - 12x + 20y - 128 = 0

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the information provided to write the general conic form equation of each hyperbola. 8) Vertices: (6, 18), (6, 2) Endpoints of Conjugate Axis: (14, 10) (-2, 10) A) −x² + y² - 12x + 20y = 0 2 B) -x² + y² - 20x - 12y - 128 = 0 C) -x² + y² + 12x - 20y = 0 D) x² - y² - 12x + 20y − 128 = 0
Transcribed Image Text:Use the information provided to write the general conic form equation of each hyperbola. 8) Vertices: (6, 18), (6, 2) Endpoints of Conjugate Axis: (14, 10) (-2, 10) A) −x² + y² - 12x + 20y = 0 2 B) -x² + y² - 20x - 12y - 128 = 0 C) -x² + y² + 12x - 20y = 0 D) x² - y² - 12x + 20y − 128 = 0
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