Use the information below to sketch the function. There is a horizontal asymptote at f(x)=1 The denominator of the function is x2-x-2 There is a y-intercept at 4. • f(-2) = f(4) = 0 • f(-6)=1 f(x) <0 when -2 0 when x < -2,-14
Use the information below to sketch the function. There is a horizontal asymptote at f(x)=1 The denominator of the function is x2-x-2 There is a y-intercept at 4. • f(-2) = f(4) = 0 • f(-6)=1 f(x) <0 when -2 0 when x < -2,-14
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![8. Use the information below to sketch the function.
• There is a horizontal asymptote at /(x)=1
The denominator of the function is x²-x-2
There is a y-intercept at 4.
• f(-2) = f(4) = 0
f(-6) 1
. f(x) <0 when -2 < x < -1,2 < x < 4
f(x)>0 when x < -2,-1 < x < 2, x > 4
●](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6374c1b4-e653-4ba1-ab76-8e557df0ec34%2F57145567-b050-4422-aabd-07f1af3366da%2Fuxpaii9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8. Use the information below to sketch the function.
• There is a horizontal asymptote at /(x)=1
The denominator of the function is x²-x-2
There is a y-intercept at 4.
• f(-2) = f(4) = 0
f(-6) 1
. f(x) <0 when -2 < x < -1,2 < x < 4
f(x)>0 when x < -2,-1 < x < 2, x > 4
●
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