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Use the information below to calculate the equilibrium constant (Ke) for the following reactions. 1. H2 (g) + Cl, (g) 2HCI (g) At equilibrium [H2] = 0.42 M, [Cl2] = 0.075 M, and [HCI] = 0.95 M 3. 2NO (g) + O2 (g) 2NO, (g) At equilibrium [NO] = 2.4 x 10 M, [0] = 1.4 x 10* M, and [NO,] = 0.95 M. 2. N2 (g) + 3H2 (g) 2NH3 (g) At equilibrium [N2] = 0.34 M, [H2] = 0.13 M, and [NH 0.19 M. 4. C (s)+ CO, (g) 2CO (g) At equilibrium [CO,] = 8.3 x 10 M, [CO] = 5.4 x 10 M.

Use the information below to calculate the equilibrium constant (Ke) for the following reactions. 1. H2 (g) + Cl, (g) 2HCI (g) At equilibrium [H2] = 0.42 M, [Cl2] = 0.075 M, and [HCI] = 0.95 M 3. 2NO (g) + O2 (g) 2NO, (g) At equilibrium [NO] = 2.4 x 10 M, [0] = 1.4 x 10* M, and [NO,] = 0.95 M. 2. N2 (g) + 3H2 (g) 2NH3 (g) At equilibrium [N2] = 0.34 M, [H2] = 0.13 M, and [NH 0.19 M. 4. C (s)+ CO, (g) 2CO (g) At equilibrium [CO,] = 8.3 x 10 M, [CO] = 5.4 x 10 M.

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Question 1 please but if you could do 2 as well thanks :) work is needed for my brain XD
NO () = 2NO, () Iproducts] [reactants] INO,1 [N.O.] Write the equilibrium expression: [0.012 MF [0.65 M] - Insert equilibrium concentrations and calculate: =2.2x10 M the units for an equilibrium constant depend on the equilibrium expression. They are often omitted altogether. Use the information below to calculate the equilibrium constant (Keg) for the following reactions. 1. H2 (g) + Cl, (g) 5 2HCI (g) At equilibrium [H] = 0.42 M, [Cl] = 0.075 M, and [HCI] = 0.95 M 3. 2NO (g) + O, (g) 2NO, (g) At equilibrium [NO] = 2.4 x 10 M, [O2] = 1.4 x 10* M, and [NO2] = 0.95 M. 2. N2 (g) +3H2 (g) 2NH, (g) At equilibrium [N2] = 0.34 M, [Hz] = 0.13 M, and [NH 0.19 M. 4. C (s) + CO2 (g) 2CO (g) At equilibrium [CO.] = 8.3 x 10 M, [CO] = 5.4 x 10 M. Find the value of the equilibrium constant (Keg) and tell whether equilibrium lies to the left or the right. 5. 2NO (g) + Br2 (g) 2NOBr (g) At equilibrium [NO] = 0.5 M, [Br2] = 0.25 M, and [NOBr] = 3.5 M. 8. PCIS (g) PCI, (g) + Cl, (g) Equilibrium concentrations are: [PCI5] = 0.25 M, [PCI ] = 9.7 x 10 M, and [Cl,] = 3.2 x 10 M. 6. 2Fe (s) + 3H,0 (g) Fe,O, (s) + 3H2 (g) At equilibrium [H2O] = 1.0 M, and (H2] = 4.5 M. 9. CO (g) + 3H, (g) CH (g) + 3H;0 (g) At equilibrium [CO] = 4.0 M. [H] = 2.8 M. [CH.] = 0.75 M, and [H-O]= 0.12 M. 7. CACO, (s) s CaO (s) + CO, (g) At equilibrium [CO:] = 4.0 x 10 M. 10. 2SO, (g) + 20; (g) 2SO, (g) At equilibrium SO:J = 2.4 x 10M. [0:] = 6.4 x 10 M, and [SO,] = 8.2 x 10 M. WS/8-3EquilibriumConstant OJolun Erickson, 2005
Transcribed Image Text:NO () = 2NO, () Iproducts] [reactants] INO,1 [N.O.] Write the equilibrium expression: [0.012 MF [0.65 M] - Insert equilibrium concentrations and calculate: =2.2x10 M the units for an equilibrium constant depend on the equilibrium expression. They are often omitted altogether. Use the information below to calculate the equilibrium constant (Keg) for the following reactions. 1. H2 (g) + Cl, (g) 5 2HCI (g) At equilibrium [H] = 0.42 M, [Cl] = 0.075 M, and [HCI] = 0.95 M 3. 2NO (g) + O, (g) 2NO, (g) At equilibrium [NO] = 2.4 x 10 M, [O2] = 1.4 x 10* M, and [NO2] = 0.95 M. 2. N2 (g) +3H2 (g) 2NH, (g) At equilibrium [N2] = 0.34 M, [Hz] = 0.13 M, and [NH 0.19 M. 4. C (s) + CO2 (g) 2CO (g) At equilibrium [CO.] = 8.3 x 10 M, [CO] = 5.4 x 10 M. Find the value of the equilibrium constant (Keg) and tell whether equilibrium lies to the left or the right. 5. 2NO (g) + Br2 (g) 2NOBr (g) At equilibrium [NO] = 0.5 M, [Br2] = 0.25 M, and [NOBr] = 3.5 M. 8. PCIS (g) PCI, (g) + Cl, (g) Equilibrium concentrations are: [PCI5] = 0.25 M, [PCI ] = 9.7 x 10 M, and [Cl,] = 3.2 x 10 M. 6. 2Fe (s) + 3H,0 (g) Fe,O, (s) + 3H2 (g) At equilibrium [H2O] = 1.0 M, and (H2] = 4.5 M. 9. CO (g) + 3H, (g) CH (g) + 3H;0 (g) At equilibrium [CO] = 4.0 M. [H] = 2.8 M. [CH.] = 0.75 M, and [H-O]= 0.12 M. 7. CACO, (s) s CaO (s) + CO, (g) At equilibrium [CO:] = 4.0 x 10 M. 10. 2SO, (g) + 20; (g) 2SO, (g) At equilibrium SO:J = 2.4 x 10M. [0:] = 6.4 x 10 M, and [SO,] = 8.2 x 10 M. WS/8-3EquilibriumConstant OJolun Erickson, 2005
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