Use the implicit differentiation to find an equation of the tangent line to the graph at the given point. 6. 4xy = 9 at (1.) 7. x3 + y3 = 6xy - 1 at (2,3)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
**Implicit Differentiation and Tangent Lines**

Use implicit differentiation to find an equation of the tangent line to the graph at the given point.

6. \(4xy = 9\) at \(\left(1, \frac{9}{4}\right)\)

7. \(x^3 + y^3 = 6xy - 1\) at \((2, 3)\)

**Explanation:** 
In problems involving implicit differentiation, we differentiate both sides of an equation with respect to \(x\), treating \(y\) as a function of \(x\). After finding the derivative, we solve for \(\frac{dy}{dx}\), which gives us the slope of the tangent line. Then, using the point-slope form of the equation of a line, we find the tangent line at the specified point.
Transcribed Image Text:**Implicit Differentiation and Tangent Lines** Use implicit differentiation to find an equation of the tangent line to the graph at the given point. 6. \(4xy = 9\) at \(\left(1, \frac{9}{4}\right)\) 7. \(x^3 + y^3 = 6xy - 1\) at \((2, 3)\) **Explanation:** In problems involving implicit differentiation, we differentiate both sides of an equation with respect to \(x\), treating \(y\) as a function of \(x\). After finding the derivative, we solve for \(\frac{dy}{dx}\), which gives us the slope of the tangent line. Then, using the point-slope form of the equation of a line, we find the tangent line at the specified point.
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