Use the image below to help find the solutuion. Around the C curve there is a line integral found to equal ∫B.dl =10^-6 T.m. Given the values of I1 I2 and I3 in the image find the value of I4 along with its direction
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Use the image below to help find the solutuion. Around the C curve there is a line integral found to equal ∫B.dl =10^-6 T.m. Given the values of I1 I2 and I3 in the image find the value of I4 along with its direction.
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- PROBLEMS 10.1 Faster than light. I stand 10 feet from a white wall, holding a laser pointer. The pointer makes a red dot on the wall directly in front of me. Then with a quick flick of my wrist (lasting only 0.1 second) I twist the laser pointer by 45°, and the red dot moves 10 feet in 0.1 second. I repeat the experiment standing 20 feet from a white wall, and the red dot moves 20 feet in 0.1 second. Finally, I repeat the experiment standing 186 000 miles from a white wall, and the red dot moves 186 000 miles in 0.1 second. In other words, the red dot moves 10 times faster than light speed. Why doesn't this motion violate the speed limit derived in this chapter?For a light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by water? glycerine= fluorite= sodium chloride=At the very end of Wagner's series of operas Ring of the Nibelung, Brünnhilde takes the golden ring from the finger of the dead Siegfried and throws it into the Rhine, where it sinks to the bottom of the river. Part A Assuming that the ring is small enough compared to the depth of the river to be treated as a point and that depth of the Rhine where the ring goes in is 12.8 m, what is the area of the largest circle at the surface of the water over which light from the ring could escape from the water? Use 1.33 for the index of refraction of water. Express your answer in meters squared. A = —| ΑΣΦ ? m²
- Diamond is known for being a particularly brilliant stone. The reason behind this is its peculiarly high index of refraction, n = 2.4. A ray of light within a diamond hits the diamond-air (n = 1) interface. Calculate the critical angle for diamond such that the ray be totally internally reflected. Critical angle for diamond-air interface = 0 Once you have determined this, compare the critical angle to the one in the figure below, which is for a glass-air interface? Knowing that glass has a smaller refractive index than diamond, which material will have a larger critical angle. n2=1 n1 =1.5 39° 90° 41.8° 45° 45° Difference between the cirtical angles between the diamond-air and glass-air interface is (report the absolute value of the difference) 0 What is the significance of this comparison with regards to the brilliance of diamond?On upper side it is sign of vectorThree polarizing plates whose planes are parallel are centered on a common axis. The directions of the transmission axes relative to the common vertical direction are shown in the figure below. A linearly polarized beam of light with plane of polarization parallel to the vertical reference direction is incident from the left onto the first disk with intensity I, = 13.0 units (arbitrary). Calculate the transmitted intensity I, when 8, 15.0°, 0,= 45.0°, and 83=57.0°. Hint: Make repeated use of Malus's law. I₁ = units 4, 8₁