Use the image as a basis which includes the circuit diagram, then use the assumed directions of the loops and currents as shown in the figure. Question 1: Create the equation using junction rule at junction a. Question 1 Choices: A. I1 + I2 + I4 = 0 B. -I1 + I2 + I4 = 0 C. I1 - I2 + I4 = 0 D. I1 + I2 - I4 = 0 E. I1 - I2 - I4 = 0 Question 2: Create the equation using loop rule in Loop 1. Question 2 Choices: A. I1R1 + I2R2 + VA = 0 B. -I1R1 + I2R2 + VA = 0 C. I1R1 - I2R2 + VA = 0 D. I1R1 + I2R2 - VA = 0 E. I1R1 - I2R2 - VA = 0 Question 3: What is the value of the current through R2? Question 3 Choices: A. 0.27 A B. 0.38 A C. 0.49 A D. 0.65 A E. 0.76 A Question 4: What is the value of the current through R4? Question 4 Choices: A. 0.27 A B. 0.38 A C. 0.49 A D. 0.65 A E. 0.76 A
Use the image as a basis which includes the circuit diagram, then use the assumed directions of the loops and currents as shown in the figure. Question 1: Create the equation using junction rule at junction a. Question 1 Choices: A. I1 + I2 + I4 = 0 B. -I1 + I2 + I4 = 0 C. I1 - I2 + I4 = 0 D. I1 + I2 - I4 = 0 E. I1 - I2 - I4 = 0 Question 2: Create the equation using loop rule in Loop 1. Question 2 Choices: A. I1R1 + I2R2 + VA = 0 B. -I1R1 + I2R2 + VA = 0 C. I1R1 - I2R2 + VA = 0 D. I1R1 + I2R2 - VA = 0 E. I1R1 - I2R2 - VA = 0 Question 3: What is the value of the current through R2? Question 3 Choices: A. 0.27 A B. 0.38 A C. 0.49 A D. 0.65 A E. 0.76 A Question 4: What is the value of the current through R4? Question 4 Choices: A. 0.27 A B. 0.38 A C. 0.49 A D. 0.65 A E. 0.76 A
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
Use the image as a basis which includes the circuit diagram, then use the assumed directions of the loops and currents as shown in the figure.
Question 1: Create the equation using junction rule at junction a.
Question 1 Choices:
A. I1 + I2 + I4 = 0
B. -I1 + I2 + I4 = 0
C. I1 - I2 + I4 = 0
D. I1 + I2 - I4 = 0
E. I1 - I2 - I4 = 0
Question 2: Create the equation using loop rule in Loop 1.
Question 2 Choices:
A. I1R1 + I2R2 + VA = 0
B. -I1R1 + I2R2 + VA = 0
C. I1R1 - I2R2 + VA = 0
D. I1R1 + I2R2 - VA = 0
E. I1R1 - I2R2 - VA = 0
Question 3: What is the value of the current through R2?
Question 3 Choices:
A. 0.27 A
B. 0.38 A
C. 0.49 A
D. 0.65 A
E. 0.76 A
Question 4: What is the value of the current through R4?
Question 4 Choices:
A. 0.27 A
B. 0.38 A
C. 0.49 A
D. 0.65 A
E. 0.76 A
![R1
10 Q
VA
R2
9 V
Loop 1
I2
I1
junction a
I4
VB
Loop 2
6 V
Loop 3
R4
15 Q
R3
16 Q](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe624db12-d092-466d-88b6-51e01cb47283%2F1059ab9a-d51c-4a98-b440-9a14e136e797%2Fo85eqt8_processed.png&w=3840&q=75)
Transcribed Image Text:R1
10 Q
VA
R2
9 V
Loop 1
I2
I1
junction a
I4
VB
Loop 2
6 V
Loop 3
R4
15 Q
R3
16 Q
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