Use the identities A = ANS and S = BUB and a distributive law to prove the following. (a) A = (ANB) U (ANĒ) A = AN--Select- V = AC --Select-- v UB = ---Select-- VU(AN B) (b) If BCAthen A = BU (AN B). From part (a), A = (AN B) U (A N B). If BCA, then ANB = --Select-- v, so A = -Select-- vU (AN B). (c) Further, show that (AN B) and (AN B) are mutually exclusive and therefore that A is the union of two mutually exclusive sets, (A N B) and (A N B). (AN B) n (AN B) = An(-Select--- vnB) =-Select-- v. Thus the two sets are mutually exclusive, and from part (a), A is the union of these two mutually exclusive sets. (d) Also show that B and (A N B) are mutually exclusive and if BCA, A is the union of two mutually exclusive sets, B and (AN B). Bn (ANĒ) = A n ---Select-- v nB) = ---Select--- v. Thus the two sets are mutually exclusive, and from part (b), A is the union of these two mutually exclusive sets.
Use the identities A = ANS and S = BUB and a distributive law to prove the following. (a) A = (ANB) U (ANĒ) A = AN--Select- V = AC --Select-- v UB = ---Select-- VU(AN B) (b) If BCAthen A = BU (AN B). From part (a), A = (AN B) U (A N B). If BCA, then ANB = --Select-- v, so A = -Select-- vU (AN B). (c) Further, show that (AN B) and (AN B) are mutually exclusive and therefore that A is the union of two mutually exclusive sets, (A N B) and (A N B). (AN B) n (AN B) = An(-Select--- vnB) =-Select-- v. Thus the two sets are mutually exclusive, and from part (a), A is the union of these two mutually exclusive sets. (d) Also show that B and (A N B) are mutually exclusive and if BCA, A is the union of two mutually exclusive sets, B and (AN B). Bn (ANĒ) = A n ---Select-- v nB) = ---Select--- v. Thus the two sets are mutually exclusive, and from part (b), A is the union of these two mutually exclusive sets.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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