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Use the graph to find the limit L (if it exists). If the limit does not exist, explain why. (If an answer does not exist, enter DNE.) h(x) = + x2 3 -1

Use the graph to find the limit L (if it exists). If the limit does not exist, explain why. (If an answer does not exist, enter DNE.) h(x) = + x2 3 -1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Use the graph to find the limit L (if it exists). If the limit does not exist, explain why. (If an answer does not exist, enter DNE.) h(x) = + x2 3 2 1 (a) lim h(x) X-2 O The limit does not exist at x = 2 because the function approaches different values from the left and right side of 2. O The limit does not exist at x = 2 because the function value is undefined at x = 2. O The limit does not exist at x = 2 because the function is not continuous at any x value. O The limit does not exist at x = 2 because the function does not approach f(2) as x approaches 2. O The limit exists at x = 2. (b) lim h(x) x-1 L O The limit does not exist at x = 1 because the function does not approach f(1) as x approaches 1. O The limit does not exist at x = 1 because the function approaches different values from the left and right side of 1. O The limit does not exist at x = 1 because the function is not continuous at any x value. O The limit does not exist at x = 1 because the function value is undefined at x = 1. O The limit exists at x = 1.
Transcribed Image Text:Use the graph to find the limit L (if it exists). If the limit does not exist, explain why. (If an answer does not exist, enter DNE.) h(x) = + x2 3 2 1 (a) lim h(x) X-2 O The limit does not exist at x = 2 because the function approaches different values from the left and right side of 2. O The limit does not exist at x = 2 because the function value is undefined at x = 2. O The limit does not exist at x = 2 because the function is not continuous at any x value. O The limit does not exist at x = 2 because the function does not approach f(2) as x approaches 2. O The limit exists at x = 2. (b) lim h(x) x-1 L O The limit does not exist at x = 1 because the function does not approach f(1) as x approaches 1. O The limit does not exist at x = 1 because the function approaches different values from the left and right side of 1. O The limit does not exist at x = 1 because the function is not continuous at any x value. O The limit does not exist at x = 1 because the function value is undefined at x = 1. O The limit exists at x = 1.
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