Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Title: Evaluating Function Values Using Its Graph**
**Objective:** Use the graph of the function \( f \) shown to the right to find \( f(-1) \), \( f(0) \), and \( f(1) \).
---
**Task:**
Using the graph of the function \( f \) provided:
- Determine \( f(-1) \)
- Determine \( f(0) \)
- Determine \( f(1) \)
**Graph Explanation:**
The graph is plotted on a coordinate system with the x-axis ranging from -10 to 10 and the y-axis ranging from -10 to 10. The function \( f \) is represented by a blue curve.
1. To find \( f(-1) \):
- Locate -1 on the x-axis.
- Identify the corresponding point on the graph directly above or below \( x = -1 \).
- The y-coordinate of this point is \( f(-1) \).
2. To find \( f(0) \):
- Locate \( 0 \) on the x-axis.
- Identify the corresponding point on the graph directly above or below \( x = 0 \).
- The y-coordinate of this point is \( f(0) \).
3. To find \( f(1) \):
- Locate \( 1 \) on the x-axis.
- Identify the corresponding point on the graph directly above or below \( x = 1 \).
- The y-coordinate of this point is \( f(1) \).
**Function Values:**
- \( f(-1) = \) [Box for input]
- \( f(0) = \) [Box for input]
- \( f(1) = \) [Box for input]
**Detailed Graph Analysis:**
1. **At \( x = -1 \)**:
- The curve intersects the y-axis at approximately \( y = -10 \).
- Therefore, \( f(-1) = -10 \).
2. **At \( x = 0 \)**:
- The curve intersects the y-axis at approximately \( y = 3 \).
- Therefore, \( f(0) = 3 \).
3. **At \( x = 1 \)**:
- The curve intersects the y-axis at approximately \( y = -4 \).
- Therefore, \( f(1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e2935af-1329-4dfa-9560-8781a8a0c5be%2F9a83a29a-b09a-4bcf-93f2-825f8900ae6a%2F34hj7zd_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Evaluating Function Values Using Its Graph**
**Objective:** Use the graph of the function \( f \) shown to the right to find \( f(-1) \), \( f(0) \), and \( f(1) \).
---
**Task:**
Using the graph of the function \( f \) provided:
- Determine \( f(-1) \)
- Determine \( f(0) \)
- Determine \( f(1) \)
**Graph Explanation:**
The graph is plotted on a coordinate system with the x-axis ranging from -10 to 10 and the y-axis ranging from -10 to 10. The function \( f \) is represented by a blue curve.
1. To find \( f(-1) \):
- Locate -1 on the x-axis.
- Identify the corresponding point on the graph directly above or below \( x = -1 \).
- The y-coordinate of this point is \( f(-1) \).
2. To find \( f(0) \):
- Locate \( 0 \) on the x-axis.
- Identify the corresponding point on the graph directly above or below \( x = 0 \).
- The y-coordinate of this point is \( f(0) \).
3. To find \( f(1) \):
- Locate \( 1 \) on the x-axis.
- Identify the corresponding point on the graph directly above or below \( x = 1 \).
- The y-coordinate of this point is \( f(1) \).
**Function Values:**
- \( f(-1) = \) [Box for input]
- \( f(0) = \) [Box for input]
- \( f(1) = \) [Box for input]
**Detailed Graph Analysis:**
1. **At \( x = -1 \)**:
- The curve intersects the y-axis at approximately \( y = -10 \).
- Therefore, \( f(-1) = -10 \).
2. **At \( x = 0 \)**:
- The curve intersects the y-axis at approximately \( y = 3 \).
- Therefore, \( f(0) = 3 \).
3. **At \( x = 1 \)**:
- The curve intersects the y-axis at approximately \( y = -4 \).
- Therefore, \( f(1
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