Use the given values Air as an ideal gas flows through the turbine and heat exchanger arrangement. Steady-state data are given on the figure and on the table. Stray heat transfer and kinetic and potential energy effects can be ignored. a) Determine the power developed, ? ̇ in Turbine 2 Find the rates of entropy production, ?̇ each in kW/K, for b) Turbine 1 and c) Heat exchanger
Use the given values Air as an ideal gas flows through the turbine and heat exchanger arrangement. Steady-state data are given on the figure and on the table. Stray heat transfer and kinetic and potential energy effects can be ignored. a) Determine the power developed, ? ̇ in Turbine 2 Find the rates of entropy production, ?̇ each in kW/K, for b) Turbine 1 and c) Heat exchanger
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
Use the given values Air as an ideal gas flows through the turbine and heat exchanger arrangement. Steady-state data are given on the figure and on the table. Stray heat transfer and kinetic and potential energy effects can be ignored.
a) Determine the power developed, ? ̇ in Turbine 2
Find the rates of entropy production, ?̇ each in kW/K, for
- b) Turbine 1 and
- c) Heat exchanger
- d) Which component contributes more to inefficient operation of the overall system? How do you know?
![W1 = 10,000 kW
Wn = ?
Turbine
Turbine
P3 = 4.5 bar
T3 = ?
T2 = 1100 K
P2 =5 bar
T4 = 980 K
P4 = 1 bar
Air
in
1
www
2
T1= 1500
Ts= 1480 K
9.
K
Heat exchanger
ps = 1.35 bar
VT = 1200 K
P6= 1 bar
sin
Air
in
State
5
units
Turbine 1
Turbine 2
Heat Exchanger
K
1500
1100
1369
980
1480
1200
bar
20
5.0
4.5
1.0
1.35
1.0
kJ/kg
1635.97
1161.1
1478.28
1023.3
1611.8
1277.8
s°
kJ/(kg K)
3.44516
3.07732
3.33504
2.94468
3.42892
3.17888
kg/sec
21.1
21.1
21.1
21.1
20
20](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7394dfd6-2eea-4eca-9714-4745c241a205%2Fcf139cee-ec25-4b12-a737-0874b3f7d316%2F76j3tf4_processed.png&w=3840&q=75)
Transcribed Image Text:W1 = 10,000 kW
Wn = ?
Turbine
Turbine
P3 = 4.5 bar
T3 = ?
T2 = 1100 K
P2 =5 bar
T4 = 980 K
P4 = 1 bar
Air
in
1
www
2
T1= 1500
Ts= 1480 K
9.
K
Heat exchanger
ps = 1.35 bar
VT = 1200 K
P6= 1 bar
sin
Air
in
State
5
units
Turbine 1
Turbine 2
Heat Exchanger
K
1500
1100
1369
980
1480
1200
bar
20
5.0
4.5
1.0
1.35
1.0
kJ/kg
1635.97
1161.1
1478.28
1023.3
1611.8
1277.8
s°
kJ/(kg K)
3.44516
3.07732
3.33504
2.94468
3.42892
3.17888
kg/sec
21.1
21.1
21.1
21.1
20
20
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