Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fa to reject the null hypothesis). The test statistic in a left-tailed test is z = - 1.83. O A. 0.0672; fail to reject the null hypothesis O B. 0.0336; reject the null hypothesis O C. 0.9664; fail to reject the null hypothesis O D. 0.0672; reject the null hypothesis Next

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).

The test statistic in a left-tailed test is \( z = -1.83 \).

Options:
- A. 0.0672; fail to reject the null hypothesis
- B. 0.0336; reject the null hypothesis
- C. 0.9664; fail to reject the null hypothesis
- D. 0.0672; reject the null hypothesis
Transcribed Image Text:Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is \( z = -1.83 \). Options: - A. 0.0672; fail to reject the null hypothesis - B. 0.0336; reject the null hypothesis - C. 0.9664; fail to reject the null hypothesis - D. 0.0672; reject the null hypothesis
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