The GRASP METHOD - Gr13 Use the given information to calculate the enthalpy of reaction for the following reaction:P4010 (S) + 6PCIs (s) → 10Cl3PO (g)(1) P4 + 6Cl₂ → 4 PCI3(2) P4 +502 → P4010(3) PCl3 + Cl2 → PCIs(4) PCl3 + 1/2O2 → CI3POΔΗ°= - 1272 kJAH°= -2915 kJΔΗ°= -125 kJΔΗ°= -267 kJ

Given thermochemical equations are (1) P4 + 6Cl2 ---> 4PCl3 ; ∆H° = -1272 KJ (2) P4 + 5O2…

Use the given information to calculate the enthalpy of reaction for the following reaction: P4010 (S) + 6PCls (s) → 10C3PO (g) (1) P4 + 6Cl₂ → 4 PCI3 (2) P4 +502 P4010 (3) PCl3 + Cl2 → PCIs (4) PCl3 + ½/202 → Cl3PO ΔΗ°= - 1272 kJ ΔΗ°= - 2915 kJ ΔΗ°= -125 kJ AH = -267 kJ

Use the given information to calculate the enthalpy of reaction for the following reaction: P4010 (S) + 6PCls (s) → 10C3PO (g) (1) P4 + 6Cl₂ → 4 PCI3 (2) P4 +502 P4010 (3) PCl3 + Cl2 → PCIs (4) PCl3 + ½/202 → Cl3PO ΔΗ°= - 1272 kJ ΔΗ°= - 2915 kJ ΔΗ°= -125 kJ AH = -267 kJ

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Question

The GRASP METHOD - Gr13

Use the given information to calculate the enthalpy of reaction for the following reaction:
P4010 (S) + 6PCIs (s) → 10Cl3PO (g)
(1) P4 + 6Cl₂ → 4 PCI3
(2) P4 +502 → P4010
(3) PCl3 + Cl2 → PCIs
(4) PCl3 + 1/2O2 → CI3PO
ΔΗ°= - 1272 kJ
AH°= -2915 kJ
ΔΗ°= -125 kJ
ΔΗ°= -267 kJ

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